Hmm, I shall try my best to solve. :))
So, we need our numbers to be in the form of a^b where a is a prime number, and b is one less than a prime number.
If a = 2, then b can be 1, 2, 4, 6. (4 options)
If a = 3, then b can be 1, 2, 4, 6. (4 options)
If a = 5, then b can be 1, 2, 4. (3 options)
If a = 7, then b can be 1, 2. (2 optinos)
If a = 11, then be can be 1, 2. (2 options)
From there, any a from 11 - 31 will have 2 options for b (1, 2).
4+4+3+21*2 = 53.
Someone please check this, I'm really not confident, but I hope this helped.
=^._.^=
