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shut up (other mean guest) you fucking b***h

Your face is the best website

wdym your face?

Im banned too so Agreed :)

(2/5)E  =  (6/7)N

(7/6) (2/5)E  =  N

(14/30)E  =  (7/15)E   = N

E - 36  =  N  + 20

E - 36  =  (7/15)E  +  20

E  -  (7/15)E  =  20  +  36

(8/15)E   =   56

E  =  (15/8)(56)

E  =  15  ( 56/8)

E  =  105   =   what  he started with

So.....he  ended  up  with    105 - 36  =   $69

Lets say E is Elvis's money and N is Noah's Money
Start by making an equation:
2/5•E=6/7•N
And make a second equation:
N+20 = E - 36
N + 56= E
You can derive this from the second sentence.
Then plug in N+56=E into the first equation:
2/5(N+56)=6/7 N
Multiply by 35 on both sides to cancel the denominators
14(N+56) = 30 N
14 N + 14 • 56 = 30 N
14 • 56 = 16 N
Divide both sides by power of 2 till N is isolated so the calculation isn't so messy.
14 • 7 = 2 N
7 • 7 = N
49 = N
Reread the question now to see what the question was about:
We need to find elvis's money at the end
That is equal to 49+20 = 69
So the answer is $69

Agreed

I don't know too it confuses a lot of people

thx!  ur right

Note  that   triangles  MNP   and  ONP   are  both right triangles

We  have  that

MN^2  =  NP^2  + MP^2          and      NO^2  = NP^2   +  PO^2  

13^2  =  12^2 +MP^2                           37^2   = 12^2  +  PO^2

169  =  144   +  MP^2                          1369  =  144  + PO^2

169 - 144  =  MP^2                               1369  - 144  =  PO^2

25  = MP^2                                            1225  =    PO^2                    take  the  sqrt rt of both sides

5  =  MP                                                   35  = PO

Note  that   MP  + PO  =  MO   =  40  =  the  base length

So

Area  = (1/2) height * base  =  (1/2)(NP) (MO)  = (1/2) (12) (40) =  240  units^2

yeah, but I still kind of don't understand it completely.

See   heureka's excellent  solution, here :

https://web2.0calc.com/questions/help_73560#r2

See  the  following image  ( not to scale)

Call the length  of  the longer  base,  AB =  P  and the length  of  the  shorter base,  GF =  Q

Then  AF  =   Q  +  ( P  - Q)  / 2  =  (P + Q)  / 2   =   the  median length   =  M

So....since the  median  =  the  height, we  have  right  triangle AFD  such  that

AF^2  +  FD^2  =   AD^2          where  AF, FD =  M     and   AD   = 12

M^2  + M^2   =  12^2

2M^2  =  144

M^2  =  72

M  =  6sqrt (2)   =  height

So....the  area  =  (1/2)  height  * (sum of the bases)  =  height *  (sum  of bases)/2   =

height  *  median  =  

(6sqrt (2) )  ( 6sqrt (2))   =     36  * 2   =   72 units^2

why do you have negative points?

Area is \(πr^2\)

By inspection .....note  that  if  b  =  2      and  c  = 4    we have

x^2  +  ( 2  + 4/2) x  +  4    =    0

x^2  +  4x   +  4   =     0

(x + 2) ^2   =   0

So.....the one root  =  -2 

Simplifying  the  sum....we  have that.......

( abd)(acd)(bcd)   + ( abc)(acd)(bcd)  +  ( abc)(abd)(bcd)  +  ( abc)(abd)(acd)

_______________________________________________________________  =

                        (abc) ( abc)  ( acd) ( bcd)

(abcd)^2  ( a  +  b +  c  + d)                     (a + b + c + d)

_________________________     =      ____________

      (abcd)^3                                               abcd

By  Vieta

(a + b + c + d)  =   - (-7)  =  7

And

abcd  =  -4

So   we  have

  7

 __   =        -7  /  4

-4

Assuming you want to solve for x. Assuming it's just 16/2x - 1 (not 16/(2x - 1). 

16/2x = 8/x

-1 + 7 = 6

8/x + 6 = 11 

subtract 6 from both sides

8/x = 5

8 = 5x so x = 8/5

is it 6???