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suppose f is a polynomial such that f(0)=47, f(1)=32

$f(2) = -13$ and 

$f(3)=16$

What is the sum of the coefficients of ?

Suppose f is a polynomial such that 

$f(0) = 47$

$f(1) = 32$

$f(3)=16$

 and . What is the sum of the coefficients of ?

Can't see the polynomial. 

I read the question wrong, going to retry. :((

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What exactly do you need? I can help!

Not corect though, but intreasting method.

256 (Sorry for not showing any work, I did it in my head and a caculator)

BBG BBG BGG BGG is our only way of splitting it up. 

To make our groups, 6!*6!/2/2/2/2, but since some groups are the same, 6!*6!/2/2/2/2/2/2 = 8100. 

8100 ways of making groups, 4*3*2 of giving colours.

8100*4*3*2 = 194400

Edit:

I read the question wrong, it's 3 groups of 4, not 4 groups of 3. 

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NVM I found 2 ways to do it(My dad helped me, we talked about it all through supper.)

The way I used was just countnig, not cpunting the opisite and then subtracting.

Boys:

1.) 3 2 1   = 360

2.) 2 2 2   = 90

Girls:

1.) 1 2 3   = 60

2.) 2 2 2   = 90

(Each number is how many people in each group, and then I used combinintry.)

360 x 60 + 90 x 90 = 29700 ways!

The other way is solving they ways that DON'T work. I'm not going to explain it but I can put a screenshot of their explantion.

- WillBill

Woah, I am really messing up lately. 

Any idea how to do this problem?

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The answer was -9. 

Sorry it says: "and there is a non-zero real number $d$"

Area = 10² cm²

https://web2.0calc.com/questions/math-help_97950 The question is answered here

For the square plot of land, the area is \(s^2\), and the side lengths are \(6x^3\), so \(6x^3 \cdot 6x^3 = 36x^6\).

For the rectangular plot of land, the area is \(l \cdot w\), and the length and width are \(3x^5\) and \(7x^2\), so \(3x^5 \cdot 7x^2 = 21x^7\).

If \(x\) is 3, then we put 3 for x.

\(36 \cdot 3^6 = 36 \cdot 729 = 26244\)sq ft

and

\(21 \cdot 3^7 = 21 \cdot 2187 = 45927\)sq ft.

So, the rectangular plot of land has a larger area.

3 divided by 1/4 is 12, so he can make 12 bows.

3÷1/4=12

Well, what do we know?

a + 2b + 2c = 3

2a + 3b + 6c = 4

I'm just going to assume a = 1.

1 + 2b + 2c = 3

2b + 2c = 2

2 + 3b + 6c = 4

3b + 2c = 2

b = 0

c = 1

We're looking for a d, where 1x + 0d + 1xd = x. 

x + xd = x

d = 0 hopefully. :))

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Wouldn't she make more muffins than cupcakes?

You're welcome. :))

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Thanks!

We're looking for the GCD of 112 and 64. 

112 = 2*2*2*2*7

64 = 2*2*2*2*2*2

The greatest divisor is 2*2*2*2 = 16. 

So our answer is 16. :))

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If the number of episodes are the same in each season, then 2x will be the number of episodes taped in 2 seasons.