Turns out that the largest angle is 66.468 (3 dp ) deg.
Call the angle OAC alpha say, and run that round the triangle,
OAB = 60 - alpha, OBA = 180 - 115 - (60 - alpha), and so on.
Calling AO x, BO y and CO z, then use the sin rule twice, in triangles AOB and AOC,
equate the two to derive an expression for tan (alpha) - I got alpha = 28.3296 deg.
From that, using the sin rule in the three triangles, calculate x, y an z.
I got (to 4 dp) x = 0.6063, y = 0.5793, z = 0.5236.
Then the cosine rule to calculate the largest angle.