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You can reflect square ABCD over line WY, then rotate it around O 45 degrees clockwise.

If

\(\log_2(x)=7~\text{find}~ \log_8(x)=y\)

\(\begin{array}{|lrcll|} \hline (1) & x &=& 2^7 \qquad \Big(\log_2(x)=7\Big) \\\\ (2) & x &=& 8^y \qquad \Big(\log_8(x)=y\Big) \\ & x &=& 2^{3y}\\ \hline & x = 2^7 &=& 2^{3y}\\ & 2^7 &=& 2^{3y} \quad & | \quad \text{compare exponent}\\ & 7 &=& 3 y \\ & \mathbf{y} &=& \dfrac{7}{3} \\ & \mathbf{\log_8(x)} &=& \dfrac{7}{3} \\ \hline \end{array}\)

Since angle AEB = DEC (vertical angles), ABE = CDE by SAS. 

Can you take it from here?

=^._.^=

Set the number of friend is x, the number of marbles is y.

everyone 11 marbles, left 6 marbles

So      11x + 6 = y     (1)

everyone  14 marbles, red 12 marbles

So      14x - 12 = y     (2)

according to (1), (2)

     11x + 6 = y      =>     x = 6

     
     14x - 12 = y              y = 72

So there are 6 friends, 72 marbles.

You need to go back and review your unit circle trig functions......to explain how the answers are derived would be QUITE lengthy on the forum !

Nope....that is incorrect too....   look at my graph.....   did you enter the points correctly ???????????

Slope y-axis intercept form    y = mx + b

Y axis intercept, b, is 16 (from the graph)     so answer #3

A basket contains some white, red, and black balls. There are 15 white and red balls. There are 18 red and black balls. The number of black and white balls is 9. Find the number of balls for each color.

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w + r = 15           w = 15 - r          15 - r + 18 - r = 9         r = 12

b + r = 18            b = 18 - r

w + b = 9

w = 3            r = 12         b = 6

A carton of oranges is to be shared among some family members. If each family member gets 5 oranges, there will be 3 oranges left in the carton. If every family member gets 7 oranges, there is a shortage of 7 oranges. How many members are there in this family? How many oranges are there in this carton?

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7x - 7 = 5x + 3       (x => number of family members)

x = 5

There are 5 family members and 28 oranges.

I don't think you offended anyone.

There is nothing wrong with offering suggestions or promoting discussions.   

If you click "copy image address" and open it in another tab, you can still see the picture. 

The square root of 2x is greater than 3 and less than 4. How many integer values of x satisfy this condition?  

3 is the square root of 9 and sqrt(2x) has to be greater than 3 so 2x has to be greater than 9.  

4 is the square root of 16 and sqrt(2x) has to be less than 4 so 2x has to be less than 16.  

So 2x can be 10, 11, 12, 13, 14, or 15.  But wait!  x has to be an integer, so 2x has to be even.  

That means 2x can be 10, 12, or 14, so x can be 5, 6, or 7. 

So the answer to "how many" is THREE.  

_.

Let  x^y=a,y^x=b. Then, a+1=b, 2a=b+7 so 2a=a+8 which means a=8,b=9 so x=2,y=3.

We have 3

The correct answer is 4/7.

AHHHHH

How do you find the inverse of its own function???

SQUARE ROOT ....not the SQUARE    

THen you should check the points  you posted in your question, because 4/5 is incorrect ....

  Here is a graph:

https://www.desmos.com/calculator/uhmyrqcqxa