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The probability of J/Q/K is 1/13, and the probability of red is 1/4, so the probabilit of J/Q/K/red is 1/13 + 1/4 = 17/52.

The solutions are (7 + sqrt(5), 7 - sqrt(5)) and (7 - sqrt(5), 7 + sqrt(5)).

Everything looks right to me.  Good job!

a = 6

b = -5

c = 4

Let the age of the first elephant be a

Let the age of the second elephant be b

Let the age of the tortoise be x.  

From the given information, we have 

x = a + b + 52

x+10 = 2(a+10+b+10)

Simplifying both, we have x=a+b+52 and x+10 = 2(a+b)+40, x = 2(a+b) + 30.  

Subtracting the two, we have a+b-22 = 0, so a+b = 22.  

This means that x = a+b +52, or 22+52, or 74 years old.  

this isnt even hw ://

https://web2.0calc.com/questions/please-help-asap-and-explain

Guest, you're literally posting your homework, your whole worksheet on this forum. Seriously, can you please try and do it yourself, and then ask for help? You're truly not helping yourself learn. 

thanks!

Updated #2, it was initially wrong I updated

TYSM!! This is a great help :)))

(1) $g(f(4)) = g(-1) = \boxed{3}$

(2) $g(h(-8)) = g(-6) = \boxed{5}$

(3) $f(g(3)) = f(7) = \boxed{-7}$

(4) $f(g(-2)) = f(-8) = \boxed{-127}$

(5) $f(g(8)) = f(4) = \boxed{48}$

(6) $f(g(8)) = f(4) = \boxed{80}$

(7) $f(g(-3)) = f(13) = \boxed{2i \sqrt{3}}$

(8) $g(h(4)) = g(63) = \boxed{3 \sqrt{7}}$

XY = 9          AX = 16          AX = 16         

(XY)² = (BX)(AX)

81 = 16(BX)

BX = 5¹/₁₆

AB = 10¹⁵/₁₆

$(y+6) + n = 12$

$12 + n = 3y$

$y + n = 6$

$n = 3y - 12$

$y + (3y - 12) = 6$

$4y - 12 = 6$

$4y = 18$

$\boxed{y = 4.5}$

y+6+x=12, y+x=6

12+x=3y, 3y-x=12

4y=18

y=9/2

JP

$\frac{67 + 52 + x}{3} = 70$

$119 + x = 210$

$x = 210 - 119$

$\boxed{x = 91}$

x-axis and y-axis are two sides of the triangle. 

So, you should substitute x=0 and y=0 in 2x+y=8

substituting x=0 gives you y=8, (height of triangle) substituting y=0 gives us x=4 (base of triangle)

Area=(1/2)(8)(4)=16

JP

Thanks both of u!

⚡️

67 + 52 + x = 210

x = 91

70*3=210

67+52=119

210-119=91

he needs a 91 on his next test

A sequence with \(a_1 = 1\) is defined by the recurrence relation
\(a_{n+1} = 2^n + a_n\) for all natural numbers \(n\).
If \(a_{23} = p\), then what is \(p\)?

\(\begin{array}{|rcll|} \hline a_1 &=& 1 \\\\ a_2 &=& 2^1+a_1 \\ &=& 2^1+1 \\ &=& 2^2-1 \\\\ a_3 &=& 2^2+a_2 \\ &=& 2^2+2^2-1 \\ &=& 2*2^2-1 \\ &=& 2^3-1 \\\\ a_4 &=& 2^3+a_3 \\ &=& 2^3+2^3-1 \\ &=& 2*2^3-1 \\ &=& 2^4-1 \\\\ a_5 &=& 2^4+a_4 \\ &=& 2^4+2^4-1 \\ &=& 2*2^4-1 \\ &=& 2^5-1 \\ && \dots \\ \mathbf{a_n} &=& \mathbf{2^n-1} \quad | \quad n = 23 \\\\ a_{23} &=& 2^{23} - 1 \\ \mathbf{a_{23}} &=& \mathbf{8388607} \\ \hline \end{array}\)

1. x is original price

    0.7x=96*0.7=67.20

2. length is 4, rectangular floor area is 32/3

32/3 divided by 4=8/3

JP

When three standard dice are tossed, the numbers x, y, and z are obtained.

Find the probability that xyz=180.