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7/7 or 2/3 (SAME AMOUNT) because peter gave 2/5 that equals to 85$  and andy gave 28$ to she will have to give 7/7 or 2/3

S : A = 3 : 2

(3x+12)/(2x+26) = 3/5

Solve for x

4 * 4/5 = 16/5  units²

If she gave away 150, that means there were 150 sets of 3

    150 *16 = 150*16 = 2400   - 450*3  = 1050         (450 *3 is the cost of goods sold)

1235- 1050 = 185     at   5 profit each = 37 single copy buyers

The possible values of c are 11 and -13.

The 12th roots of unity are s, u, v.

Here is  a  Venn diagram of this situation:   Can you anser this now?

1+2+3+4+5.....+12 =   78

 78/12 = 6.5

x = starting amount

x - 105     amount after wallet

3/5 (x-105)     amount after t shirt     and this equals 1/3 x        

3/5 (x-105) = 1/3 x

4/15x = 63

x = 236.25

2/5 ( 236.25 - 105) =  52.50    <==== shirt price

This is a "partition" problem of 14 into 5 parts. There are 23 such partitions as follows:

10 + 1 + 1 + 1 + 1 = 14
9 + 2 + 1 + 1 + 1 = 14
8 + 3 + 1 + 1 + 1 = 14
8 + 2 + 2 + 1 + 1 = 14
7 + 4 + 1 + 1 + 1 = 14
7 + 3 + 2 + 1 + 1 = 14
7 + 2 + 2 + 2 + 1 = 14
6 + 5 + 1 + 1 + 1 = 14
6 + 4 + 2 + 1 + 1 = 14
6 + 3 + 3 + 1 + 1 = 14
6 + 3 + 2 + 2 + 1 = 14
6 + 2 + 2 + 2 + 2 = 14
5 + 5 + 2 + 1 + 1 = 14
5 + 4 + 3 + 1 + 1 = 14
5 + 4 + 2 + 2 + 1 = 14
5 + 3 + 3 + 2 + 1 = 14
5 + 3 + 2 + 2 + 2 = 14
4 + 4 + 4 + 1 + 1 = 14
4 + 4 + 3 + 2 + 1 = 14
4 + 4 + 2 + 2 + 2 = 14
4 + 3 + 3 + 3 + 1 = 14
4 + 3 + 3 + 2 + 2 = 14
3 + 3 + 3 + 3 + 2 = 14

There are   2⁴ = 16 possible outcomes

there are only 2 ways to get 3 heads in a row:   t  h h h    and    h h h t

2/16 = 1/8 as posted

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x²(6+1) + ((28) - (15) - (6x) - 2)

7x² + (11 - 6x)

7x² - 6x + 11

Wasn't sure whether 7x4 is 28x or 28, specify whether you are multiplying or multiplying with an "x".

This graph might help explain:

1.25 = 1 dose

40 = ?

40/1.25 = 32

1 dose x 32 = 32 doses

Hope this helps

A fraction line is really just a divide by sign  

example

$1)\quad \frac{5}{6}=5\div 6\\ 2) \quad 5\frac{3}{4}=5+3\div4$

Now just put it in any calc and you will get the decimal equivalent.

Some calculators, like this Web2.0 calc   will do this for you automatically.

2x(x - 10) = -50 + 2x

$2x(x - 10) = -50 + 2x\\ 2x^2-20x-2x+50=0\\ 2x^2-22x+50=0\\ 1x^2-11x+25=0\\ x=\frac{11\pm\sqrt{121-100}}{2}\\ \text{sum of the roots =}11$

With one roll of a fair 12-sided die, the probability of any one number appearing is EQUALLY likely:

Therefore, the probability is 1 / 12

The probability of getting 3 heads in a row is:

1/2 x 1/2 x 1/2 ==1 / 8

Square side => a

8a/15 + a +15a/8 = 17

Solve for a.

Let f(y) = y^4 -3y^3 +y - 3 and g(y) = y^4 - 5y -10. Find f(y) + 2g(y) . Write your answer as a polynomial with terms of decreasing degree.

Hello Guest!

$f(y) + 2g(y)=y^4 -3y^3 +y - 3+2y^4 - 10y -20\\ \color{blue}f(y) + 2g(y)=3y^4-3y^3-9y-23$

Hello guest!

For you a little help in LaTeX:

Answered on the 10th  by apsi...

And we are still waiting for you to respond.

B is not strictly one element less than C.