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Volume of larger cube  10 * 10 * 10 = 1000 cm^3

Volume of a smaller cube   2 * 2 * 2 = 8 cm^2               1000/8 = 125 smaller cubes

Surface area of large cube = 10*10 * 6 = 600 cm^2

                        smaller cube = 2 * 2 * 6 = 24 cm^2    

                                                                 and there is 125 of them , so total surface area = 125 * 24 = 3000 cm^2

600 / 3000 = 1/5

You are looking for the time at which they will both be the same distance

rate X time = distance  

for the first runner   distance = 25 miles + 7.5 m/hr * x        where x is the time in hours

   theis equals the total distance for the second runner    23  miles + 8.3 m/hr * x

25 + 7.5 x    =   23 + 8.3 x       solve for x  (  in hours)  when they will be at the same distance .....

1/2 c   =   43 + 1/3 d

c = 86+ 2/3 d  

c+ d = 821

(86+ 2/3 d )  + d = 821

                5/3 d   = 735

                       d = 441         then   c = 380

i get nothing

Mising important info in your question......

Can you be more specific?

Arrange given line to y = mx+b form   where m = slope

y = 2x -2    slope = 2   parallel slope is the same = 2

y = mx +b

y = 2x + b     sub in the point given to calculate 'b'

10 = 2(1) + b

b = 8

y = 2x + 8

i dont get that

25 + 7.5 x    =   23 + 8.3 x       solve for x  ( hours)

Acceleration is change in velocity over change in time

28 m/s  /   4 sec =   7 m /s²

The maximum possible of the GCD ==26, when n==21

x^2 + 8x +4      Multiply by 1.75

1.75 x^2 +  14 x + 7

The numbers start at: 1,000,000,006,  1,000,000,015,  1,000,000,024......and so on. But there no fixed pattern that I know! However, I wrote a short computer code and it gave me a total =1,285,713,534 integers whose digit sums are divisible by 7.

How many stamps did John have at first?

Hello PCGeorge!

\(j=t+50\\ j+35=5(t-35)\\ j=5t-210\\j=t+50\\ 5t-210=t+50\)

\(t=65\\ j=115\)

115 stamps did John have at first.

  !
 

7^20188 mod 10^10==5598672801 these are the last 10 digits.

Chad has total 14 stickers and half of these

are silver.

So, number of silver stickers which Chad has

= 14 ÷ 2 = 7

Now, Sarah has 29 more stickers.

Total number of stickers Sarah has

=(14+29)=43

Number of silver stickers Sarah has

=(7−5)=2

To get same number of silver stickers as

Chad, Sarah needs 5 more silver stickers. 
Now, let x be the number of stickers Sarah

would bought. Then,

 40x/100 = 5

⇒ 2x = 25

⇒ x = 12.5

⇒ x ≈ 13

Then, total number of stickers

=43+13

=56

the required answer is 56.

https://www.jiskha.com/questions/1870671/a-baker-baked-240-tarts-the-ratio-of-the-number-of-chocolate-tarts-to-the-number-of

The solution is (a,b,c) = (3,5,-2).

DC = 6.

idc no more guy thank you my boi

Let  c  be the number of chocolate puffs he baked and let  s  be the number of strawberry puffs he baked.

Since he baked a total of 1060 puffs, we can make the following equation

c + s  =  1060

Let  x  be the number of puffs he gave away for each type.

So since he was left with 2/7 of the chocolate puffs after giving away  x  chocolate puffs, we can say:

c - x  =  \(\frac27\)c

And since he was left with 1/5 of the strawberry puffs after giving away  x  strawberry puffs, we can say:

s - x  =  \(\frac15\)s

The total number of puffs left is going to be 1060 - 2x. So now we need to find  x  by solving this system of three equations.

s - x  =  \(\frac15\)s          ⇒          s - \(\frac15\)s  =  x          ⇒          \(\frac45\)s  =  x          ⇒          s  =  \(\frac54\)x

c - x  =  \(\frac27\)c          ⇒          c - \(\frac27\)c  =  x          ⇒          \(\frac57\)c  =  x          ⇒          c  =  \(\frac75\)x

c + s  =  1060              Now we can substitute  \(\frac54\)x  in for  s  and  \(\frac75\)x  in for  c

\(\frac75\)x  +  \(\frac54\)x  =  1060

\(\frac{53}{20}\)x   =   1060

x   =   1060 * \(\frac{20}{53}\)

x   =   400

And so the total number of puffs left  =  1060 - 2x  =  1060 - 2(400)  =  1060 - 800  =  260

area of triangle  =  (1/2) * ( base ) * ( height )

area of triangle  =  (1/2) * ( 4 cm ) * ( 3 cm )

area of triangle  =  6 cm²

sumfor(n, 1,100,n^2009) mod 10^10=7532998500 these are the last 10 digits

Use distance formula

d^2 = 800    

800 = ( x-7)^2 + ( 21-4)^2

800 = x^2 -14x+49 + 289    

x^2  - 14x -462 = 0       <=======  Now use Quadratic Formula to solve for 'x'

10x+4=8        subtract 4 from both sides of the equations

10x   +4 -4   = 8 -4

10x = 4      divide both sides by 10

x = 4/10

x = 2/5    or   .4