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I have actualy seen this question on my CTY class called "Middle School Competitive Math." I am confused too!

Hello macabresubwoofer,

what have you tried yourself? Describe your problem, please.

Are that your homework, then you're wrong here. But I see, this does not look like a homework.

Straight

What answer did YOU get ?    I got the price as 800     ( 8 dollars)

Hello,

"You need to check your question very carefully." like Melody said,

note this and correct these errors.

Straight

Hello macabresubwoofer,

describe your problem, what have you tried yourself?

Straight

You need to check your question very carefully.

You have not labeled your trapezium (trapezoid to you)  properly.  It only has 3 letters.

And that makes me wonder if some of the other letters are incorrect as well.

Find the standard form of the equation for the circle with the following properties. Center (−4,−3/2) and tangent to the x-axis

Hello macabtesubwoofer!

\(P_c(-4,-1.5)\)

\(f(x) =\pm \sqrt{{\color{blue}1,5}^2-(x-{\color{blue}4})^2}-\color{blue}1,5\\ (y+1.5)^2=1.5^2-(x-4)^2 \)

The standard form of the equation for the circle is

\((x-4)^2+(y+1.5)^2=1.5^2\)

  !

hint: draw it and then it is easy to see the radius

then use the formula

the centre of circle is (-5,5) and radius 2 so 

(x+5)^2+(y-5)^2=2^2 

$ 26.02 * 1.24 = total amount to pay

-2.4 *(6.1)   change in 'y'

48x + 47x = 427.5

x=4.5 hours

You have not understood my logic straight my logic Straight.

Try writing it out, as a multiplication, and see what happens if B=0  you will find that the answer will not be C430  it will have to be C440.

becasue 3*8=24 

So B is not 0

The answer is incorrect though.

3x^2-x+8=0    IS the quadratic equation

roots ( also called 'zeroes') are      1/6 +- sqrt (95)i /6

That's so smart (not sure if it's allowed tho) :))

I was struggling with 3 3 3 = 10. 

=^._.^=

The sum of all possible values of a is 10.

Is it legal to use a decimal point as a math operation?    

3 3 3 = 10

3 ^ (3 – 3) = 1.0   

_.

*** edit ***

    Now....can you solve for 'a'   <==== which is the price of adult tix

a -150 = c

325 c   +  175 a   = 351250

325 ( a - 150)   + 175 a = 351250      Now....can you solve for 'a'   <==== which is the number of adult tix