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I was looking for x and y, not the actal answer.

\((2 + 3)(2^2 + 3^2)(2^4 + 3^4)(2^8 + 3^8)(2^{16} + 3^{16})(2^{32} + 3^{32})(2^{64} + 3^{64})\\ \color{blue}=1.17901845777\cdot 10^{61}=2^x+3^y\)

Thanks 

Note that Vieta's can be generalized for degree $n.$ Try finding a formula.

\(ax^2 + bx + c = a(x-r_1)(x-r_2) \\ ax^2 + bx + c = a(x^2 + x(-r_1 - r_2) + r_1 r_2) \\ ax^2 + bx + c = a \cdot x^2 + a \cdot x(-r_1 - r_2) + a \cdot r_1 r_2 \\ a(-r_1-r_2)=b \\ (-1)(a)(r_1+r_2)=b \\ r_1 + r_2 = - \frac{b}{a} \\ a \cdot r_1 r_2 = c \\ r_1 r_2 = \frac{c}{a}\)

WIRE COSTS   96/16    cents per inch

96/16    *   22 =    ______  cents

=  OC

Hello Guest,

calculate this on our home page 👤Web 2.0 scientific calculator (0calc.com) {https://web2.0calc.com/} .

Straight

*AKA is profitable.

. . . correction:

An example, 

AKA has for \(1l\) 2£ , whereas 33% like it        and

EKA has for \(1l\) 1.75£ , whereas 30% like it .

To buy EKA would be more profitable because the difference (33% - 30% =) 3% has a worth of 0.3£, 

1.75£ + 0.3£ = 2.05£ . Change :

AKA has for \(1l\) 2£       and

EKA has for \(1l\) 2.05£ .

EKA is profitable.

The volume of PABCD = 32√33

nice

A = -16

BC / AB = CE / AE

Ohhhhkkkkkk thank you so muchh!!!

La - ti - da    ....

E train time  160 units  =  (t + w)       length of train is t     w is the distance you walked

W train          40 units   = (t- w)

Add the equations      200 units = 2t      t = 100 units train length

who can help

We can solve this pretty easily by using casework.

Case 1: Starting with F in the middle

If we start with F in the middle, there are 4 choices for F. Then we have 2 choices for O, 3 choices for the second O, and 2 choices for the T.

Case 2: Starting with F in the corner

If we start with F in the corner, there are 4 choices for F. Then we have 1 choice for O, 3 choices for the second O, and 2 choices for T.

Adding these up, we have 24 + 48 = 72 ways to spell FOOT.

Hello Guest,

In Fizic school there was a math competition, with 5/7 of the students in the whole high school participating.

There were 3 rounds to master in order to win the tournament.

From the first to the 2nd round only 1/6 of the whole students who participated made it, from the 2nd round to the 3rd round only 16/400.

This tournament was won by 5 students in total.

Find out the number of students who participated and the number of students in Fizic High School.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Students in Fizic High School \(\Rightarrow\) 1050 students

Students that participated \(\Rightarrow\) 750 students

Shorten the fraction \(\frac{16}{400}\) into \(\frac{1}{25}\) .

At the end 5 students won the tournament.

\(\mbox {Multiply 5 by 25 and divide 1. }\)

\(5 \cdot 25 = 125\)

\(125 : 1 = 125 \mbox { (Any number divided by 1 is the same.) }\)

\(\mbox {Multiply 125 by 6 and divide 1. }\)

\(125 \cdot 6 = 750\)

\(750 : 1 = 750 \mbox { (Any number divided by 1 is the same.) }\)

Thus, 750 students from Fizic High School participated.

\((750 : 5) \cdot 7 = 1050\)

Thus, there are a total of 1050 students at Fizic High School.

Straight

Thanks! :D

8/48 * 60 = 10 marbles

Hello Guest,

Thomas has brought 189 small marbles,
his friend Jonas wants 60 marbles,
but he only got 8/48 of the marbles he wanted. How many marbles did Jonas get?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Shorten the fraction \(\frac{8}{48}\) to \(\frac{1}{6}\) .

Of the 60 marbles requested, Jonas only got \(\frac{1}{6} \cdot 60=10\) of them.

Edit: The method of solution was written in the final sentence.

Straight

        p     n   d   q

1  = (25, 4, 0, 0)
2  = (20, 5, 0, 0)
3  = (15, 6, 0, 0)
4  = (10, 7, 0, 0)
5  = (5, 8, 0, 0)
6  = (0, 9, 0, 0)
7  = (25, 2, 1, 0)
8  = (20, 3, 1, 0)
9  = (15, 4, 1, 0)
10  = (10, 5, 1, 0)
11  = (5, 6, 1, 0)
12  = (0, 7, 1, 0)
13  = (25, 0, 2, 0)
14  = (20, 1, 2, 0)
15  = (15, 2, 2, 0)
16  = (10, 3, 2, 0)
17  = (5, 4, 2, 0)
18  = (0, 5, 2, 0)
19  = (15, 0, 3, 0)
20  = (10, 1, 3, 0)
21  = (5, 2, 3, 0)
22  = (0, 3, 3, 0)
23  = (5, 0, 4, 0)
24  = (0, 1, 4, 0)
25  = (20, 0, 0, 1)
26  = (15, 1, 0, 1)
27  = (10, 2, 0, 1)
28  = (5, 3, 0, 1)
29  = (0, 4, 0, 1)
30  = (10, 0, 1, 1)
31  = (5, 1, 1, 1)
32  = (0, 2, 1, 1)
33  = (0, 0, 2, 1)