All Answers 358098 Answers

There are 44,672 possible values.

You meant to ask for angle QRC, which is 25 degrees.

300 multiples of 4     400 multiples of 3    

       100 multiples of 12  (these are counted twice)

1200 - 400 - 300 + 100 = 600 left

This was answered before
https://web2.0calc.com/questions/let-p-x-x-2-q-x-2x-3-1-and-r-x-7x-4-5x-3-6x-2-find-p-q-x-r-x#r1

Nevermind i got the answer 137/111

123,456,789/1,000,000,000      Approx   10/81

\(x\in \mathbb R\ |\ x<-\frac{7}{3}\)

Good answer i dont know if you wrong or correct but I got \(\quad 8x^5+33x^3\)

I think 64. Anyone correct me if im wrong

\(\left(-\infty \:,\:-\frac{7}{3}\right)\)One of these 2 should be correct

Let x be the total monthly budget.

Then, amount spent on car = x * 1/6

Amount spent on housing = x * 3/8

Amount spent on entertainment = x * 1/4

Total amount spent = x ( 1/6 + 3/8 + 1/4) = x (4 + 9 + 6)/24 = x * 19/24

Balance amount spent on groceries = x — x * 19/24 = 5/24 x

Now, 5/24 x = $ 250

So, x = 250/5 * 24 = $1200

i think 25 man

Gideon spends 1/6 of his monthly budget on his car, 3/8 of his budget on housing, 1/4 of his budget on entertainment, and the remaining $250 on groceries. What is the total amount of his monthly budget?

Monthly budget = x

x/6 + 3x/8 + x/4 = 19x/24

250 = 5x/24       Solve for x

A teacher uses 2/3 of her yearly supply of construction paper during the first quarter. She then uses 5/7 of what's left during the second quarter. During the third quarter, she uses 3/4 of what she has left (from the end of the second quarter). How much construction paper does the teacher have left for the fourth quarter of the school year?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Construction paper => x

2x/3 + 5x/21 + 6x/84 = 82x/84

Construction paper left = x/42    or    1/42

Hello Guest!

\(8x^5+17x^3=\color{blue}x^3(8x^2+17)\)

  !

\(\frac{1}{\sqrt{2}} +\frac{3}{\sqrt{8}} + \frac{6}{\sqrt{32}}\\ = \frac{\sqrt{32}}{\sqrt{32}} \times \left( \frac{1}{\sqrt{2}} +\frac{3}{\sqrt{8}} + \frac{6}{\sqrt{32}}\right) \)

now expand the bracket and simplify.

\((50 + 72i)^2 - (50 - 72i)^2\\ =50^2+(72i)^2+(2*50*72i)\quad -[50^2+(-72i)^2-(2*50*72i)]\\ =2*(2*50*72i)\\ =14400i \)

Couldn't have said it any better! :)

The answer is 14400 i.

Please re-write your question in plain text so that I understand it. 

N mod 3 == 2

N mod 5 == 4, solve for N

LCM{3, 5} ==15 

N ==15c  +  14,  where c ==0, 1, 2, 3........etc.

Since the number of eggs is between 50 and 60, then we have:

[15 *3  +  14] ==59 eggs

The solutions are 3, -3, 8, and -8.

As a fraction, it is equal to 10/81.

The expression is equal to 4*sqrt(2).

The answer is 17200*i.