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Jan 3, 2022
 #2
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I know you can do third-grade math, EP.  I’ve seen you do it before –and you usually get the correct answer. This question is literally for the third-grade: it’s on page 20 of this pdf. https://www.edhelper.com/3rd_grade/3rd-grade-math-worksheets.pdf

 

It’s very unlikely this question is asked by a third-grade student. These questions, like most of the other brain-dead questions of this type, are asked by remediated high school students.

 

This is how remediated students do their homework: post it on web2.0calc.com: paste the question, wait for an answerer (compelled by OCD) to answer, then copy the answer on the assignment paper.

 

It’s best not to answer it.

 

On an open forum, there is no convenient method to prevent the posting of these brain-dead questions. But, if the questions do not receive answers then this will discourage the posters.

 

 

 

--. .-

Jan 3, 2022
 #1
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first circle:

 

(x-2)2 + (y+1)= 16

 

becomes:

 

(x2 - 4x + 4) + (y2 +2y + 1) = 16

x2 - 4x + y2 + 2y + 5 = 16

x2 - 4x + y2 + 2y = 11

 

second circle:

 

(x-2)2 + (y-5)2 = 17

 

becomes:

 

x2 - 4x + 4 + y2 - 10y + 25 = 17

x2 - 4x + y2 - 10y + 29 = 17

x2 - 4x + y2 - 10y + 23 = 11

 

we have x2 - 4x + y2 + 2y = 11     and     x2 - 4x + y2 - 10y + 23 = 11

both equal 11 so they equal each other

 

x2 - 4x + y2 + 2y = x2 - 4x + y2 - 10y + 23

 

x2, -4x, y2 cancel out

 

2y = -10y +23

12y = 23

y = 23/12

 

23/12 is the y - value of both of the points where the circles intersect (A and B)

 

choose one of the equations to plug in 23/12 as y. This will find the x-values of both of the points

i choose (x-2)2 + (y+1)= 16

but you can do other one too

 

(x-2)2 + ((23/12)+1)= 16

(x-2)2 + ((23/12)+(12/12))= 16

(x-2)2 + (35/12)= 16

(x-2)2 + 1225/144 = 2304/144

(x-2)2 = 1079/144

(x-2) = sqrt(1079/144)   OR   (x-2) = -sqrt(1079/144)

x = sqrt(1079/144) + 2   OR   -sqrt(1079/144) + 2

 

These are the x values of the two points where the circle intersect

I guess AB means the line segment between them

So AB2 is the length of the line segment squared which means we subtract the two x-values then square. We dont have to worry about the y-values since they are the same for both points

 

( (sqrt(1079/144) + 2) - (-sqrt(1079/144) + 2) )2

( (sqrt(1079/144) + 2 + sqrt(1079/144) - 2) )2

( sqrt(1079/144) + sqrt(1079/144) )2

( 2sqrt(1079/144) )2

4(1079/144)

1079/36

 

or in decimal

 

29.97222....

Jan 3, 2022

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