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For some reason whenever I'm doing an actual test I make silly mistakes but then casual problems I don't. Lol.

This is pretty easy. All numbers with 3 as a factor terminate when divided by 3. So find the amount of numbers that are multiples of 3 in your range. 474 is the 158th multiple of 3, so 158 numbers.

oops lmao

I think you forgot 3 own both in step 3. It's 21 since you do 16+8=24 as you did but then subtract 3 to get 21 as the answer.

6 students take both languages. 43+48+n=97 and this simplifies to n=97-91 or n=6.

2 3/8 + 9/12 = 2 3/8 + 3/4 = 2 3/8 + 6/8 = 3 1/8

I think this will help: https://web2.0calc.com/questions/there-are-100-students-in-south-high-school-south-high-school-offers-only-chinese-and-spanish-there-are-8-more-students-in-chinese-than-in

if you search the entire question up on google, you might be able to find that the question has been answered on this or other math forums before.

can you help me with 2 and 3/8 +9/12 please

1. so, 16 people own cats, 8 people own dogs, and 3 people own both. 
2. that means the 3 people who own both that the 16+8 people who are counted for cats and dogs 
3. you simply add 16+8 =24, then subtract 2 to get 22. 

THANK YOU THANK YOU

8/24=(1*8)/(3*8)=1/3 * 8/8=1/3

So 8/24 =1/3.

0,12-->0% win-->n=4

2,13-->13.3%win-->n=5

4,15-->21.05%win-->n=6

6,16-->27.27%win-->n=7

8,17-->32%win-->n=8

10,18-->35.7%win-->n=9

12/19-->38.71%win-->n=10

14/20-->41.18%win-->n=11

16/21-->43.24%win-->n=12

18/22-->45%win-->n=13

We can clearly see the win percentage goes above 40% after week 11. So n is 11.

Could you explain how you got to that answer please?

Well, this question can be written with several equations. We can say m is the amount of money to write m>=200. We can also say 80+(3/4)(m-80)>m-200 which becomes 3m/4+20>m-200 or 20>m/4-200 or 220>m/4 or finally m<880. We can check this by checking whether 80+(3/4)(880-80)>(880)-200. If we simplify that, we get 680>680 which is not true since they are equal. Now we have set the upper limit. We can also check whether 200 dollars itself works. We can do 80+3/4(200-80)>(200)-200 which works. This means all the numbers from 200 up to 880, including 200 but not 880, work as possible value. 

The answer as an interval is [200,880).

I'm pretty sure this question is impossible. We can say t=800+x where t is your truck and x is her trucks and then write t<=(1/5)(4x) which is also t<=4x/5. Let's assume t=4x/5. Then if we solve the equation we get x=-4000 which is clearly not possible since the truck shouldn't carry a negative weight. Also, if t=4x/5 -1, we subtract 1 to put an equal sign instead of a < sign, then we get x=-4005 and x is decreasing in value(since it is negative) and so we can never get a positive answer. This means the problem shouldn't be possible. 

This I think should be simple. I hope I'm not getting too overconfident but I think it's just (3/6)*(2/5)*(1/4)=1/20.

So the chance of everyone getting a red card is 1/20.

It's in japanese. But I'm not sure exactly what they're saying. Something about a question about math I think.

The answer is 5/24.

f(17) = 3(17) -1 = 50

f(50) = 149

f(149) = 446

b/a = i*sqrt(2), c/a = i/2.

Well, Ig you could just keep doing the function, but I am sure there is a more efficient way. If you just repeat the function you do f(f(f(17)))=f(f(3(17)-1))=f(f(50))=f(3(50)-1)=f(149)=3(149)-1=446.

So f(f(f(17)))=446.

Even if there's a more efficient way, no matter what, you should get 446 as your answer.

Sorry Melody, this was the problem that I was talking about which wasn't letting me type after the -pi/2. The thing should say "Furthermore, -pi/2

    to solve        y = 10 - x    

       then   x^2 - y^2 = 56

                  x^2 - (10-x)^2 = 56   <===== solve for 'x'   then 'y' = 10 - x

They sum to 360

q   +    5q+15    +   3q+25     +   3q + 70   =  360     now solve for 'q'    then use 'q' to calculate the angles to see which is largest....

3x^2+72x+4     re-arrange to:

3 (x^2 + 24x)   +   4    complete the square

3 (x+12)^2   - 428       <===== take it away !