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This is evidently from a test. A test is made to test YOUR capabilities, not ours. You should not be asking these questions, and we should not be answering these questions.

3x^8.   means degree 8

Parity Rules:

pos x pos = pos

pos x neg = neg

neg x pos = neg

neg x neg = pos

Both \(1\over2\) and \(12\) are positive, so the product must be \(\color{brown}\boxed{\text {positive}}\)

We know that \(\angle BCE =30\). We know that \(BC\) and \(CE\) are the same length, so\(\triangle{CEB}\) is isosceles. This means that \(\angle CBE=\color{brown}\boxed{75^{\circ}}\)

We know that since the angle of a square is 90 degrees, and an equilateral triangle has an angle of 60. So, we know that BEC = 90-60 = 30. 

CE = CD (because it is an equilateral triangle)

CD = CB (because it is a square)

CE = CB

Thus, CBE = CEB

Since a triangle's angles add up to 180, we know:

CBE + CEB + 30 = 180

CBE + CEB = 150

Since CBE and CEB are equal, they both equal 150/2 = 75

This means that Angle CBE = 75 degrees.

Let me know if I did anything wrong!

But how is it positive 

Part A: \({1\over2}\times{12}=\color{brown}\boxed{6}\)

Part B: \(\color{brown}\boxed{\text{positive}}\)

I may be wrong here, as Probability is not my strongest subject, but it seems to me that the solution should be quite simple. Let's say you pick any random point. You will notice that only 2 other points are 1 unit away... all the others are farther. So, assuming that you can't pick the same point twice, you have 7 options for picking another point, and as 2 are not going to work, the answer is 5/7.

Let me know if I did anything wrong!

You want to have a quadratic one one side that is equal to zero. You can do this by adding 2-x to both sides, leaving you with:

x^2 + 2x + 2 >= 0

You will notice that this is not factorable but it does not need to be factored. You can see that the discrimant, which is the term under the square root of the Quadratic Formula (b^2 - 4ac) is negative. When the Discrimant is negative, it means that the quadratic has no real solutions, or no real x-intercepts. Since the a value is positive, thus meaning that the parabola opens upwards, we know that all values of x result in positive y values. So, the answer to the question is:

(-inf,inf), or, in other words, all values of x will suffice.

Let me know if I did anything wrong!

Use the exponent rule \(x^{a} \cdot x^{b} = x^{a+b}\).

\(x^2 \cdot x^{-8} = x^{2-8} = x^{-6} = \boxed{\frac{1}{x^6}}\)

We have the equation y = 3x/7 + b, since we know that the slope is 3/7. Plug in the point (-14, 0):

0 = 3(-14)/7 + b

0 = -6 + b

b = 6

The line is y = 3x/7 + 6.

Similarly, we have a rhombus with short diagonal 2(10/3) = 20/3 and long diagonal 2(10) = 20. From there it shouldn't be too hard to calculate the area.

Four right triangles with height   10 / 3      base = 10       Can you calculate the area of a triangle?   ..... then multiply by four.

x + 3y = - 4

3x -10y = 36      Multiply first equation by -3      then add to second equation to get

    -19y = 48       Now you can solve for y      then   x

Area of triangle = 1/2 *  base * height            ( ft²)

(3b -2)(5b +1)

ya i tried i got a but i dont know if its right

What have YOU tried on this one?    You are posting an awful lot of Questions.....we are here to help, but not DO your homework or test questions....

Here are two iso triangles

 65   65     50

 65   57.5  57.5

(29 + 43) * 15 = ___________ people

x^-8   is equal to   1 / x⁸

x² / x⁸  =  1/x⁶    or    x^-6

Y = 1/x          ( or was that SUPPOSED to be   y is inversely proportional to x²  ??)     

If x is halved

Y = 1/(.5x)

Y = 2/x = 2 * 1/x      Y is doubled

X increases 20%

Y = 1/(1.2x)  =   5/6  * 1/x      Y becomes  5/6 of the original

Thank you!

Which of the following possibilities will form a triangle?

 a.Side = 15 cm, side = 7 cm, side = 7 cm 

b.Side = 15 cm, side = 7 cm, side = 9 cm

c. Side = 14 cm, side = 6 cm, side = 7 cm 

d.Side = 14 cm, side = 6 cm, side = 8 cm  

The sum of any two sides of a triangle must be greater than the third side.  That's the rule.   

Therefore, only b. can form a triangle.  

_.

It would be a recatangle because either way you cut it at its bases both cuts will become rectangles 

SOLUTION: A plane perpendicular to the bases will intersect both bases on a straight line and the curved edge on two parallel lines. The resulting cross section is a rectangle. SOLUTION: A plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases.