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Actual factors: 1, 181, 32761

Ur question is wrong!!! >:(

32761 Is prime

https://www.2dtx.com/prime/prime32761.html

32761 divided by 1, 32761, gives no remainder. They are integers and prime numbers of 32761, they are also called composite number.

Here is what I think is the answer

p = k / d^4

35 = k / (375⁴)

k = 6.92 x 10 ^11 m⁴ - uW

1.5 km = 1500 m

p = 6.92 x 10 ^11 m⁴ - uW  / (1500 m)⁴  = 1.37 x 10^-1 uW

(This applies to radar waves returning to the reciever/transmitter.....I believe wave power diminishes inversely to the SQUARE of the distance.....so this may not be the answer you are looking for.....it may be   p = k / d^2

     in this case the answer would be 2.187 uW )

The Quadratic Formula is a method of calculating the value(s) of 'x' that solve the quadratic of form

y = a x²  + b x   + c      the x values can be found by plugging   a ,  b and c into the formula and computing:

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

The quadratic formula is a general formula used for solving the quadratic equation: x = − b ± b 2 − 4 a c 2 a . Note that: if x2 = k, where k ≥ 0, then or same as x = ± k , where ± means “plus or minus.”

60 - 46 = 14 dollars to buy data

14/3 = 3 2/3     since he can only buy whole gigabytes, he can only buy  ~ 3 Gb data

N mod 5==4

N mod 6 ==5

N mod 7==0

N mod 8==1

N mod 9==2

N mod 10==9

Using "adjusted" CRT + MMI, we have:

2,520n +  2009,  where n==0, 1, 2, 3.......etc.

when n==0, the smallest N that satisfies all 6 congruences is:

N==2009

 = x^2 + 10x   = 0

     x ( x + 10)     = 0      x = 0    or  -10  

if i have 15 mins in every class and i have eight classes ho long is my day?     

 15   min        8   class 

 ––  ––––  x  ––  ––––  =  120 minutes you spend in class, aka 2 hours   

  1   class      1      1  

However, your day is still 24 hours long, just like it always is,  

except if you have to reset the clock for Daylight Saving Time. 

_.

Well, why don't you just list the numbers with one "9" in them?

509, 519, 529, 539, 549, 559, 569, 579, 589, 590, 591, 592, 593, 594, 595, 596, 597, 598 ==18 such numbers.

The inequality is x - y + 2 > 0.

x = 3.333333...

y = x^2 + 23x -3        complete the square for 'x'

y =   (x+11.5)^2  - 132.25  -3

y =   (x+11.5)² - 135.25     <===== finish from here !

its is 7

= t^2 +2t + 9             bowl shaped parabola ....   minumum value will be at  t = -b/2a   =  - 2 / (2*1)  = -1    

Use Vieta's calcs

ab = -5/7

a+b = -1/7

1/a + 1/b      multiply first term by b/b    second term by  a/a

b/ab  +  a/ab  =  ( b + a )/ab    sub in the red values above

1/a + 1/b   =  (-1/7) / (-5/7 ) =  1/5

30 * x = 120     divide both sides of the equation by '30' to find 'x'

Agree with geno....   I read the question as 19 consecutive EVEN integers.....   D'Oh!   

2 x 10⁶   = 2 000 000

What is the size of the pen?

Welcome back CPhill.

Shouldn't multiples of 24 be subtracted from multiples of 6 + multiples of 8, since they are already included in the totals of the two?

67 + 50 - 16 ==101 such multiples.

Ok Tiggsy I have an answer  

Can you please show us how to do it properly now :))

\(\displaystyle sum = \frac{1}{4}+\frac{2}{1+2cos\frac{2\pi}{7}}+\frac{2}{1-2cos\frac{3\pi}{7}}+\frac{2}{1-2cos\frac{\pi}{7}}\\ \\~\\\displaystyle sum \approx 8.3478346790362325\)

2/(1+2cos(2pi/7)) = 0.8900837358250465

2/(1-2cos(3pi/7)) = 3.603875471605593

2/(1-2cos(pi/7) = -2.493959207437541

0.25+0.8900837358250465+3.603875471605593+3.603875471605593 = 8.3478346790362325