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Oh wow !

Hello GingerAle!

I made a masterpiece there. Think crookedly and still get the right result! I woke up at 3 a.m. and never fell asleep again. I turned too much to chemistry and not so much to mathematics. Sorry, it was three o'clock in the morning. I recommend the studends your method! Thanks for the simple solution!

  !

Hello Asinus:

Your solution is correct, but your method is overkill. The question introduces a molar ratio and asks for the number of moles. Molar mass is not needed here, only a basic ratio formula.

Question (restated in active voice): Two (2) moles of Fe (iron) react to produce three (3) moles of Cu (copper). How many moles of copper precipitate, if 0.0125 moles of iron react?

Solution:

\(\text {Molar ratio: 2} \small \mathrm {Fe} : \normalsize {3} \small \mathrm{Cu } = \normalsize \text {0.0125} \small \mathrm{Fe} : \normalsize \text {X} \small \mathrm {Cu } \normalsize \text {; solve for X.}\\ 0.0125 \small \mathrm {Fe} * \normalsize \dfrac{3 \small \mathrm {Cu}} {\normalsize{2} \small \mathrm {Fe}} = 0.01875 \small \mathrm {Cu} \normalsize \rightarrow 1.875 \;x\; 10^{-2}\; \mathrm {moles \; Cu} \)

GA

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It seems like this is only a part of a question.

I know that the gradient of T' is  tan(theta)

so I know that the gradient of OP is  -cot(theta)

Which points are fixed?

Can you describe the situation better please?

It will have a real solution so long as  b^2-4ac is greater or equal to 0

\(b^2-4ac\ge0\\ 25-8c\ge0\\ -8c\ge-25\\ 8c\le25\\ c\le 3.125\)

If 0.0125 moles of iron solid reacted, how many 2 moles of copper solid would be produced ?

Hello Guest!

\(2 Fe + 3 CuCl_2 --> 2 FeCl_3 + 3 Cu\)

relative atomic mass

Fe   55.85 

Cu   63.54

\(2\cdot55.85g\ Fe\ \widehat =\ 3\cdot 63.54g\ Cu\\ 111.7g\ Fe\ \widehat =\ 190.62g\ Cu\\ 0.0125\ mol:2\ mol=x:190.62g\ Cu\\ x=\frac{190.62\cdot 0.0125}{2}\ g\ Cu\\ x=1.91375g\ Cu\cdot \frac{mol}{63.54g}\)

\(x=1.875\times 10^{-2}mol\ Cu\)

\({\color{blue}1.875\times 10^{-2} moles\ of\ Copper}\ solid\ would\ be\ produced.\)

  !

You're wrong!

493 is 17 x 29

I am GP-72022a, here's your answer

It's the square of 71 (71 x 71/71^2)

493 is a prime number and it cannot be factorized

Because it's factors are only 1 & 493

Factors: 1, 493

Nice Job Guest!

^.itsfree

So the ratio of \(\)Cookies:Oranges is \(4\frac{2}{7}:1\)

Hope it helps!

^.itsfree

Yes it means all of the answers for \(\sqrt{x}>12\) is x>144

Nice job proyaop!

Using order of operations "PEMDAS":

We must first do 1 x 8 / 69, this order doesnt matter. 

8/69 cannot be simplified, and 1 x 8 / 69 = 8 / 69.

1 + 8 / 69 = 69/69 + 8 / 69.

That equals to 77/69. This cannot be simplified.

Your answer is 77/69 or approximately 1.116.

1/2 base * height * length = volume

1/2 (7.8) * height * 14.3 = 786.357            solve for height

A formula for what?

  3x+8y=24          subtract 3x from both sides of the equation

8y = 24-3x           divide through by 8

y = 3 - 3/8 x

AB has compressive force =   stress = (100 + 50 + 100 + 85 + 85) kN / 8000 mm²   

BC has force  100+50 + 100 - 85 - 85    - 200 - 200 = -150  kN       a tensile force  / stress

    stress = 150 kN / 2000mm²

CD has   force   100+50+100 - 85 - 85 + 200 + 2 00 = 480 kN compressive force      stress = 480 kN / 12000 mm²

Starting with the number at A, square the number, if the answer is less than 81, check that answer.

Work your way down the list.

Remember that, if you square a negative number, the answer is positive.

area of face * lngth = volume

1/2 ( 20) (17)  * length = 1020       solve for length

x⁸ - y⁸  =  (x⁴ - y⁴)(x⁴ + y⁴)

             =  (x² - y²)(x² + y²)(x⁴ + y⁴)

             =  (x - y)(x + y)(x² + y²)(x⁴ + y⁴)

This is factored as the product of four polynomials but is not the product of four polynomials

of degree 1 because that is impossible.

It is possible to further factor my result if you are allowed to use imaginary factors.

Vertex form

a = -1   h = -2   k = 4

a negative value of 'a' will invert the parabola ( trun it upside down to a dome shaped parabola)

Try watching this.

I ahve watch 3/4 of it and it looks really good.

Remember that If 2 figures are just different by a scaling factor, then they are similar figures.