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1260 cents (might be wrong, but double checked)

1260 cents (might be wrong, but double checked)

The answer is 316,251.

https://web2.0calc.com/questions/help-pls_79519

12556 ( 60 ) , 13455 ( 60 ) , 22355 ( 30 ) , >>Total combinations = 3

>>Totals in parentheses = 150 permutations

f(x)=x^(101) + Ax + B

x^2-1=(x-1)(x+1)  so  1 and -1 are roots of f(x)

so

f(1)=0    and  f(-1)=0

solve simultaneously.

Easy peazy.

Let the time that it takes you to meet each other==T

12T  +  18[T - 1/2]==50

12T  +  18T -  9 ==  50

30T ==50 + 9

30T ==59

T ==59/30 x 60 minutes ==118 minutes after Cassie left at 8:30 AM

8:30  +  118 minutes ==10:28 AM - the exact time when you will meet.

Note: Cassie will have ridden her bike for 118 minutes and you will have ridden your bike for 118 - 30 ==88 minutes after you left at 9:00 AM.

t=/ 0. (-inf, 0)U(0, Inf) This is because if zero was substituted in, then 1-1 = 0 and 0 cannot be in the Denominator.

Note that the formula for slope is: \({ \text{rise} \over \text{run}} = {{y_2 - y_1 \over x_2 - x_1}}\)

Substituting the 2 points we know, we find the slope is: \({ 5 - 1 \over 5 - 3} = {4 \over 2} = 2 \)

This means that the y-coordinate for x = 6 is 2 higher than the y-coordinate when x = 5. 

Can you take it from here?

1 Euro ==$ 1.5

$40 / $1.5==26.67 Euros.

26.67  -  17 ==9.67 - Euros - change you get back.

The line x = -3 goes through point C on the triangle. This means point C stays the same after the reflection. 

Then just translate it 4 units right and 1 unit up:

(-3 + 4, 0 + 1)

C" = (1, 1) 

Point A after the reflection will be 4 units to the right. This is because the line of reflection is vertical, and point A is 2 units left of the line. 

(-5 + 4, 2) 

A' = (-1, 2)

Then translate it just like you did for point C:

(-1 + 4, 2 + 1)

A" = (3, 3) 

Finally, you can do the same thing in A for point B:

(-6 + 6, -1)

B' = (0, -1)

(0 + 4, -1 + 1)

B" = (4, 0) 

Let me know if you have any questions. 

let x and y represent the two integers respectively. 

we know that their sum is 24. we could then isolate for one variable:

x + y = 24

      y = 24 - x

their product would then be: 

xy = x(24 - x)

     = 24x - x² 

     = -(x² - 24x) 

     = -(x - 24x + 144 - 144) 

     = -[(x - 12)² - 144]

     = -(x - 12)² + 144

In vertex form, we can see the maximum. 

The answer is 144.

The x-intercept will always have a y-coordinate of 0. To find the x-intercepts of the two lines, substitute 0 for y: 

First line: 

   \(y = \frac{1}{3}x + 7\)

\((0) = \frac{1}{3}x + 7\)

\(-7 = \frac{1}{3}x\)

   \(x = -21\)

Second line: 

   \(y = 2x - 5\)

\((0) = 2x - 5\)

   \(5 = 2x\)

   \(x = 2.5\)

Their sum: 

2.5 + (-21) = -18.5

Let me know if you have any questions 

8+4=12, so the expression = 12 if x=2

sorry, but that's incorrect.

\(f(x) - f^{-1}(x) = x\)

The answer is 112/999.

Solving for when the quadratic is 6 gives you an answer of 4/7.

2(x+2)?

That seems to be simplified already, if you're trying to do that.

The largest value would have to be 2.  I got that intuitively.

Then I set out to prove it.

Let 

 \(z=a+bi\\ |z|=\sqrt{a^2+b^2}=1\\ a^2+b^2=1\\\)

\(z^2+1 = a^2-b^2+2abi+1\\ z^2+1 = a^2-b^2+1+2abi\\ |z^2+1| =\sqrt{ (a^2-b^2+1)^2+(2ab)^2}\\ |z^2+1| =\sqrt{ (a^2+b^2-2b^2+1)^2+(2ab)^2}\\ |z^2+1| =\sqrt{ (1-2b^2+1)^2+(2ab)^2}\\ |z^2+1| =\sqrt{ (2-2b^2)^2+(2ab)^2}\\ |z^2+1| =\sqrt{ (4+4b^4-8b^2)+(2ab)^2}\\ |z^2+1| =2\sqrt{ (1+b^4-2b^2)+(ab)^2}\\ |z^2+1| =2\sqrt{ (1-b^2)^2+(ab)^2}\\ |z^2+1| =2\sqrt{ (a^2)^2+(ab)^2}\\ |z^2+1| =2a\sqrt{ (a^2)+(b)^2}\\ |z^2+1| =2a\sqrt{ 1}\\ |z^2+1| =2a\\ \text{But a must be between 0 and 1}\\ \text{So the largest possible value of } |z^2+1| \;\;is\;\;2\)

there is probably a much better way to do it. 

12  +  12 ==24

12  x  12 ==144