All Answers 358147 Answers

I love you Cphill you just saved my math test also, why does it sometimes say "error" and then a bunch of letters and numbers after when I post a question or reply or answer?

That answer is wrong because you need to include the (-1 (it's undefined) to 1]

A closed circle includes an integer in the  interval

An open  circle excludes an integer in the  interval

So

[ - 2,  4 )

Note that triangles   PXQ  and   RXS  are similar

The scale factor of the sides of  PXQ to RXS =  sqrt (20  / 48) = sqrt ( 5 /12)

And note that sin  angle   PXS   = sin angle QXR  = sin angle RXS

So  the area of triangle   PXS =  (1/2) ( sqrt (5/12) XR) ( XS)  *sin (angle RXS)  =

sqrt (5/12) * (1/2) (XR) (XS)  sin (angle RXS) =  sqrt (5/12) [ area of triangle RXS ]

Similarly

Area of triangle  QXR  =  (1/2) (sqrt (5/12) XS) ( XR) * sin ( RXS)  =

sqrt (5/12)  * (1/2) ( XS) *XR) * sin (angle RXS)  =

sqrt (5/12)  [ area of triangle RXS ]

So....the total area =   20 + 48  +  2 sqrt (5/12) area (RXS)  =

20 + 48 +  2 sqrt (5/12) ( 48)   ≈  129.97 units ^2 

Do not post A o P S homework.  That is cheating.

I find it astonishing that this site in general would be specifically approved by a teacher and not the net in general.

there are many brilliant teaching resources in You Tube and on the net in general.  

Maybe it is a stranger danger thing idk.

Anyway, your explanation is reasonable.

Most of the time it is best to ignore Gingers tirades.

I might delete some of thiese posts later later for now I am just going to lock the question so that no more posts can be added.

< 5 even digits >    

Is it standard mathematical practice to consider zero an even digit?   

I'm not trying to be a smartazz, I mean that as a genuine question. 

Terry, Carl and Dave bought a present for their friend. Terry paid 1/3 of the total amount paid by Carl and Dave. Carl paid 2/5 of the amount paid by Terry and Dave. If Terry paid $24 less than Dave for the present, find the cost of the present.

Let the amount that Terry paid = P

Let the amount that  Dave paid = P + 24

The amount that Carl paid = (2/5) ( P + P  24)  →  (2/5) (2P + 24)

So....the amount that  Terry paid =  (1/3) (2/5) ( 2P + 24)

So

P =   (1/3)  [  (2/5)(2P + 24) + ( P + 24) ]      multiply both sides by 3

3P  = (2/5) (2P + 24) + ( P + 24)           multiply through by 5

15P =  2 (2P + 24) + 5 ( P + 24)

15P = 4P + 48 + 5P + 120

15P  - 4P - 5P  =  48 + 120

6P  =  168

P = 168 / 6 =     28 =  what Terry paid

P + 24 =  52  =  what Dave paid

(2/5) ( 28 + 52) =  (2/5) (80) =  32  = what  Carl paid

The present cost      28 + 52 + 32  =   $112

Small circle = 10 / 2 = 5

Small circle area = 3.14 * 5 * 5 = 78.5

Large circle = 5 + 11 = 16

Large circle area = 3.14 * 16 * 16 = 803.84

Shaded area = 803.84 - 78.5 = 725.34 yd^2

Sean  has S bookmarks

Greg has 7S

So    when Greg gives Sean  15  we have that

7S - 15  =  S + 15

7S - S  =   15 + 15

6S = 30

S = 30 / 6   = 5

7S    =  35

Together they have    5 +  35 =   40 bookmarks

Let the longest side =  L

So   one side = (1/3)L   and the other =   L -13

So

L + (1/3)L + L  -13   = 85

(2 + 1/3)L  =  85 + 13

(7/3)L  =  98

L  = 98 ( 3/7)  =   (98 / 7) * 3  =  14* 3  =  42

(1/3)L =  14

L = 13 =   29

Radius of small circle =  5 yd

Area =  pi (5)^2 = 25 pi

Radius of large circle =   (5 + 11) yd =  16 yd

Area  = pi (16)^2  = 256 pi

Shaded area =  (256 - 25) pi  =  231 pi  =  231 * 3.14 =   725.34 yd^2

thats wrong?

g (x) =  f (x + 7) =    (x + 7)^7  - 3(x + 7)^3  + 2    =

1x^7 + 49 x^6 + 1029 x^5 + 12005 x^4 + 84032 x^3 + 352884 x^2 + 823102 x + 822516

Just add the   red integers to get your answer

5.60/2.80 = 2 (the number of days in the first scenario is twice that of the second)
5.60 x 2n + 39.20 = 2.80 x n + 140
n = (140 - 39.20)/(5.60 x 2 - 2.80) = 12
12 x 2 x 5.60 + 39.20 = 173.60
or
12 x 2.80 + 140 = 173.60

Answered.

5.60/2.80 = 2 (the number of days in the first scenario is twice that of the second)
5.60 x 2n + 39.20 = 2.80 x n + 140
n = (140 - 39.20)/(5.60 x 2 - 2.80) = 12
12 x 2 x 5.60 + 39.20 = 173.60
or
12 x 2.80 + 140 = 173.60

x^2  + 7 =  56

x^2  =  49         take both roots

x = 7     or x = -7

Sum of solutions for x   =  0 

I made a mistake, the answer is [-1/2,1].

Please stop these links, just solve it or are you too lazy?

Triangles BDA and BDC are under the same height...so....their areas are to each other as their bases

So   area of   BDA =  (1/(1 + 2)) [ABC]  = (1/3) [360] = 120

Note that sin  angle BEA =  sin angle DEA

And  BE = ED

And AE= AE

So

area of  triangle  BEA = (1/2) (BE)(AE) sin (BEA)

area of triangle  AED =  (1/2) (ED)(AE) sin ( DEA)

So  area of  triangle  BEA  = area of trinangle  AED  

So

[AED] + [ BEA ]  = [ BDA ] 

 2 [ AED ] =   120

[ AED ]  =   60

You're all all new to math, the answer is (-1, inf) because the higher the number, the more greater is to 1. Simple logic.

You're all new to math, because the answer is actually (-1,2].