All Answers 358181 Answers

0

First you have to use the Change of Base Formula. Hence, log_x(xyz)=ln(xyz)/ln(x), etc.
Then, your equation becomes,

ln(x)/ln(xyz)+ln(y)/ln(xyz)+ln(z)/ln(xyz)=(ln(x)+ln(y)+ln(z))/ln(xyz)=ln(xyz)/ln(xyz)=1

Since, we have the same denominator we can combine everything in a single fraction then using properties of log we get the final answer.

GuestSep 10, 2013

0

1% of 1000 is 1000/100 = 10. So, yes, 8 is less than 1% in this case.

GuestSep 10, 2013

0

Microseconds are 10^-6 seconds. Thus what we have here is 7.041*10^-4*10*-6 seconds = 7.041*10^-4 microseconds

GuestSep 10, 2013

Sep 9, 2013

+6

0

woops I forgot to post the problem
56/18 divided by 7/6 divided by 4/3

freefallingSep 9, 2013

0

1+2 equals 4!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

GuestSep 9, 2013

0

the circumference is equal to pie times the diameter
so the diameter must equal 102 feet
half of the diameter is the radius so the radius is 51 feet

GuestSep 9, 2013

+259

0

Strongly recommend to read this on how to solve cubic equations:

http://mathforcollege.com/nm/mws/gen/03nle/mws_gen_nle_bck_exactcubic.pdf

scrutinizerSep 9, 2013

+259

0

(2 sqrt50 - 3 sqrt8 )^2. First you could simplify the expression: (2 sqrt{25*2} -3 sqrt{4*2} )^2 = (2 *5 *sqrt{2} -3*2* sqrt{2} )^2 = (10sqrt{2} - 6* sqrt{2} )^2 = (4sqrt(2))^2 = 16*2 = 32

scrutinizerSep 9, 2013

0

first, 5.280km= 5280m
second, 5280/80=66m <- the length of one rod, in metres

GuestSep 9, 2013

+259

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More detailed version: 2/3h-9=6-2/3h => 2 - 9*(3h) = 6*(3h) - 2 =>15*(3h) = 4 =>3h = 4/15 => h = 4/45

scrutinizerSep 9, 2013

+259

0

When something "lies between" it's always two objects (numbers) it lies in between. So, "between sqrt(26) and..."?

scrutinizerSep 9, 2013

+259

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28 = 27 + 1 = 3^3 + 1^3; 72 = 64 + 8 = 4^3 + 2^3, 1125 = 1000 + 125 = 10^3 + 5^3

scrutinizerSep 9, 2013

0

M_K2O = 2M_K + M_O = 2*39.0983 g/mol + 1.00794 g/mol = 79.20454 g/mol

GuestSep 9, 2013

+259

0

We notice here presence of roots of the power 4. Let's rearrange the expression for more comfortable use: 5^1/4 * 5^-9/4 = sqrt(4){5}*sqrt(4){1/5^9} = sqrt(4){5/5^9} = sqrt(4){5^-8} =
= 5^{-8/4} = 5^-2 = 1/5^2 = 1/25 Or even simplier: 5^1/4 * 5^-9/4 = 5^(1/4 - 9/4) = 5^(-8/4) = 5^-2 = 1/25.

5^(1/4) * 5^(-9/4)

scrutinizerSep 9, 2013

+259

0

(1.3*10^3)(5.724*10^4) = 10^7 (1.3 * 5.724) = 7.4412 * 10^7

scrutinizerSep 9, 2013

0

How about (3.00 * 108 m/s)/(27.00 * 109 Hz) = 12.0/109 m = 110 mm

Fun fact: 3.00 * 108 m/s is not the speed of light...

GuestSep 9, 2013

+259

0

Completely irrelevant presentation of statement of the problem. "In 7/8" what? Does he jog 3 OR 2/5 miles and how to understand "AND"? Specify what you meant to be posted.

scrutinizerSep 9, 2013

+259

0

By reducing both fractions to the common denominator, which is 8 and multiplying the numerator by 2 (4*2 = 8) to equalize values of both fractions we get (6 - 5)/8 = 1/8

scrutinizerSep 9, 2013

+3146

0

[input]2/3h-9=6-2/3h[/input]

adminSep 9, 2013

0

5x+x=19+5
6x=24
x=4

GuestSep 9, 2013

0

lim{x->0} (sqrt(x + 4) - 2)/x [*(sqrt(x + 4) + 2)/(sqrt(x + 4) + 2)]

lim{x->0} [(sqrt(x + 4) - 2)*(sqrt(x + 4) + 2)]/[x*(sqrt(x + 4) + 2)] =
lim{x->0} (sqrt(x + 4)^2 - 4)/[2x + sqrt(x^2 * (x + 4))] =
lim{x->0} (x + 4 - 4)/[2x + sqrt(4x^2 * (x/4 + 1))] =
lim{x->0} x/[2x + 2x*sqrt(x/4 + 1)]

lim{x->0} sqrt(x/4 + 1) = 1

lim{x->0} x/[2x + 2x*sqrt(x/4 + 1)] =
lim{x->0} x/(2x + 2x) = 1/4

GuestSep 9, 2013

Sep 8, 2013

0

ur ugly and dumb give up on life

GuestSep 8, 2013

0

Use the 10x button

GuestSep 8, 2013

0

For as much as I can see, the Web2.0 calculator does not handle scientific notation.
The "e" button shows 2.718281... which is a constant very often used in mathematics.

If you are referring to another make or model of pocket calculator, you should refer to its user manual.

GuestSep 8, 2013

0

7x + 49x/3 = 21x/3 + 49x/3 = 70x/3

There does not seem to be much else to do..

GuestSep 8, 2013

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