All Answers 358351 Answers

I drew one line down from b to d to make a 90 degree angle.

90+50=140

180-140=40^o

and that was CPhill's way, but it was wrong...

The circumference of the circle is 36pi.

Arc BD is 100 degrees as is arc AC. Arc CD and AB are therefore both 80 degree arcs.

80/360 x 36 pi = \(8\pi\).

This assumes that the latex symbol you used (\widehat, something I've never seen used outside of noting angles) means what I assume it to mean: arc.

ya

he

he

he

haha... Melody feel senses of déjà vu? 

Hey Guest, EP and Melody had a shot at this one here : https://web2.0calc.com/questions/halp-im-so-confused

Melody,

I think you have done this question before... :)

https://web2.0calc.com/questions/if-where-represents-a-base-8-digit-and-represents

The numbers that aren't in the domain of that function are \(\sqrt 7\), \(\sqrt[4]8\), the opposites of both of those, and \(\sqrt[5]9\).

The first two are cancelled out by their opposites, so the answer is \(\sqrt[5]9\).

This is equal to the square root of 2*6*110*156 = \(\sqrt {205920}\)

This is equal to \(12\sqrt{1430}\).

x can't be negative, otherwise the numerator would be imaginiary.

x can't be one to negative one, otherwise the denominator would be 0 or imaginary.

Therefore, the domain is \(x \in (1, \infty)\).

There should be five times as many cups of flour as quarts of milk.

Luke has six times as many cups of flour as quarts of milk.

BuilderBoi, your answer is correct, however I'm pretty sure to express that answer as a complex number you would write it as 

\(\frac{-5}{34}-\frac{3}{34}i\)

oh, haha I read the question wrong, just z^2 is much easier eh,

@Guest why bother asking forums when you could just use a calculator? 🤷‍♂️ Heres one https://web2.0calc.com/

@Melody

     I think what he means is, \(d\) is a base 8 digit as well as the second digit of number \(1d41\)🤷‍♂️

The answer is 21

The meaning of this question is not clear to me.

Is 1d41 a base 8 number? 

What have you done for yourself?

Thank your for resonding.

12 is a small number, I challenge you to list them.

I can se no relevance at all of 5C2. Perhaps you would like to explain?

Simplify

Hello Guest!

\((2y-1)(4y^{10}+2y^9+4y^8+2y^7 + y^6)\\ =y^6(2y-1)(y^4+2y^3+4y^2+2y+1)\\ =y^6(2y-1)((8y^3+2y^2+4y+2)y+1)\\ =y^6(2y-1)((((8y+2)y+4)y+2)y+1)\\ =y^6 (2 y - 1) (8 y^4 + 2 y^3 + 4 y^2 + 2 y + 1\\ \color{blue}=16 y^{11} - 4 y^{10} + 6 y^9 - y^6 \)

  !

It should be C5,2 but there are 2 additional cases for when both are added on the same one. We can also use complementary counting and get 16 - 4(the repeated ones)

I'll do the numerator, and you can do the denominator. 

For the numerator, let \(x = 0.{ \overline{72}}\). This means \(100x = {72. \overline{72}}\) (move the decimal point 2 places to the right)

Subtracting the 2 yields us \(99x = 72\) (the repeating parts cancel out)

Dividing by 99, we find that \(x = {72 \over 99}\)

Your answer is wrong, the number is more than the denominator, so the fraction will be greater than 1...

The expected value is \(({3 \over 4} \times 1) + (-1 \times {1 \over 4}) = \color{brown}\boxed{1 \over 2}\)

https://web2.0calc.com/questions/need-help-builderboi

Suppose you have a weighted coin in which heads comes up with probability 3/4 and tails with probability 1/4. If you flip heads, you win $1 but if you flip tails, you lose $1 What is the expected win of a coin flip in dollars?     

I don't know the formal way to solve this kind of problem, so I'll just kind of think out loud.  

The first three times you flip the coin, it's heads so you win $3. 

The fourth time you flip the coin, it's tails so you lose $1.

You've won $3 and lost $1 so you've netted $2. 

You've netted $2 and it took four flips to do it, so that comes to $0.50 per filp.  

You can reflect on whether or not this reasoning is legitimate while you wait for one of the smart ones to come along.