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Between 2000 and 2015, the number of twin births in the United States increased by 13%, to approximately 135,000. About how many twin births were there in 2000?

n=16

Week Wins Losses   

1                   3 

2                   6               

3                   9

4                   12

5            2      13

6            4       14

7            6        15

8            8         16

9            10        17

10           12       18

11          14         19

12          16         20

13           18        21

14           20       22

15           22       23

16           24       24

after 16 weeks, the team was exactly won 24/48 (50%) of the total games, so n=16.

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Hint:

expand this and see what you get

(x+5)(x-3)^2

HELP PLS HELP

The inradius of the triangle is \(\text{Area} \over \text{semiperimeter}\)

The circumradius of the triangle is \(\text{product of 3 sides} \over 4\times\text{Area}\)

Let \(\angle IAB = x\) and \(\angle IBA = y\)

We know that \(x + y + 106 = 180\), meaning \(x + y = 74\)

We also know that \(\angle C = 180 - 2x - 2y = 180 - 2(x+y)\)

So, \(\angle C = 180 - 2 \times 74 = \color{brown}\boxed{32}\)

Ohhhh, thank you so much I understand it now!

Simplify: 

\(a(x+b(x+3)) = 2(x+6)\)

\(a(x+bx+3b) = 2x + 12\)

\(ax+abx+3ab = 2x + 12\)

Equate coefficicents:

\(ab = 4\)

\(a + ab = 2\)

Solving this system, we find \(a = -2\) and \(b = -2\) so \(a + b = \color{brown}\boxed{-4}\)

Its -4 👍😎

1 = (1, 3, 5) = 9
2 = (25, 27, 29) = 81
3 = (73, 75, 77) = 225
4 = (145, 147, 149) = 441
5 = (241, 243, 245) = 729
6 = (361, 363, 365) = 1089
7 = (505, 507, 509) = 1521
8 = (673, 675, 677) = 2025
9 = (865, 867, 869) = 2601
10 = (1081, 1083, 1085) = 3249
11 = (1321, 1323, 1325) = 3969
12 = (1585, 1587, 1589) = 4761
13 = (1873, 1875, 1877) = 5625

Here's a hint: The 3 numbers can only sum to a square if the square is divisible by 3

Multiply the 1.1 degF by 11 and subtract the result from 53.7 degF

Total protein:  P = 5 oz/(soldier*day) * 600 soldiers * 5*7 days = 105,000 oz

105,000 oz = 3 oz/(soldier*day) * N soldiers * 10*7 days     Solve for N

What are the possible values of the number of dollars in the original pile of money?

Hello Guest!

There are x$ in the pile of money.

\(x-\frac{x-80}{3}>x-200\\ \frac{x-80}{3}>200\\ \color{blue}x>680\ $\)

\(x\in\{\mathbb R\ |\ 680 < x< \infty \}\)

  !

Here is one example:

You have $20 and oranges cost $3 each. At the counter, you decide to order a magazine worth $2. How many oranges can you buy?

If x is the number of oranges, then 3x + 2 <= 20.

This is by no means the only example that can be used. A Google search would likely reveal more than enough examples to reference.

Expand by distribution.

-2(8 - 7x)

= -2(8) - 2(-7x)

= -16 + 14x

2/3x - 9 = -13

2/3x = -4

2 = -4(3x)

2 = -12x

x = -1/6

0.579 * 104 = 60.216

(x - 3)(x^2 + 4x + 4) = x - 3 + x^3 - 7x + 8

x^3 + x^2 - 8x - 12 = x^3 - 6x + 5

x^2 - 8x - 12 = -6x + 5

x^2 - 2x - 17 = 0

From there, use the quadratic formula and add the roots to get the answer.

L==Lilies

R==Roses ==L  +  49

2 / 5 [L  +  49] ==3 / 4L

2 / 5L  +  19.6 ==3 / 4L

3 / 4L - 2 / 5L ==19.6

7 / 20L == 19.6

L ==19.6 / (7 / 20) ==19.6  x  20 / 7 ==392 / 7 ==56 Lilies at first

56 + 49 ==105 Roses at first.