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Edited by Melody: Explanations are better then final answers 

Thankyou guest for answering I have just removed the first line.

What is sqrt(25)? Use your calculator to get 5

What is 18/6? Use your calculator to get 3

The larger a negative number is, the smaller it is. So: - 5 is smaller that  - 2.5......and so on.

- 4 + 10 = + 6F - temp at noon

Well,

what is G(1)  ?

Hi Proaop,

\(f(6)+6f(1-6)=1+36\\ f(6)+6f(-5)=37\qquad (1)\\~\\ f(-5)-5f(1--5)=1+25\\ f(-5)-5f(6)=26\\ -5f(6)+f(-5)=26\qquad (2a)\\ -30f(6)+6f(-5)=156\qquad (2b)\\~\\ now\;\;\;(1)-(2b)\\~\\ \text{I expect you can finish it.}\)

No, I also don't see it.

It's a dissapointing question in a way, in that it's easy to spot the (or a) solution.

We are not told whether or not x and y are integers or whether or not they are both positive, but assuming they are both positive integers, the smallest possible value for x is 8.

Now, 8 cubed = 512 and 512 - 8 = 504.

Since 8 = 2 cubed, that gets you the solution x = 8, y = 2.

No clue, sorry :,)

Sum ==2 / [1 - 1/18]==36 / 17

Hmm... I see what you did there, but I still (embarrassingly) have no clue of what to do next. 

Difference of cubes: (x - y)(x^2 + xy + y^2)

x^2 + y^2 = (x + y)^2 - 2xy

(x - y)((x + y)^2 - xy)

\((x - y)(100 - xy) = 504\)

How can you take it from here? Good luck.

\(z = a + bi\) where a and b are real numbers and i is one unit in the imaginary plane.

\(2(a + bi) + 3(a - bi) = -25 - 2i\)

\(2a + 2bi + 3a - 3bi = -25 - 2i\)

\(5a - bi = -25 - 2i\)

The real number parts of the equation are equal and the imaginary parts of the equation are equal:

\(5a = -25\)

\(-bi = -2i\)

Now, we can obtain that \(a = -5\) and \(b= 2\).

Thus, \(z = -5 + 2i\).

\(x + xy^2 = 250y\)

\(x - xy^2 = -240y\)

\(2xy^2 = 490y\)

\(xy = 245\)

\(x + 60025 = 250y\) 

\(x - 60025 = -240y\)

\(120050 = 490y\)

\(y = 245\)

x = 1, 1225

\(\sqrt{50y} + 2\sqrt{18y} = 2(\sqrt{8y} + \sqrt{72y}) - 5\)

\(5\sqrt{2y} + 6\sqrt{2y} = 2(2\sqrt{2y} + 6\sqrt{2y}) - 5\)

\(11\sqrt{2y} = 4\sqrt{2y} + 12\sqrt{2y} - 5\)

\(5 = 5\sqrt{2y}\)

\(1 = \sqrt{2y}\)

If you made a latex error and the y was outside the square root, \(y = {\sqrt{2}\over2}\). If not, then \(y = {1\over2}\).

FV ==PV x  [1  +  R]^N

FV==1  x   1.05^10

FV ==1.628895  -  1  x  100 ==62.8895% total percentage increase.

5%=0.05

so each year, it multiplies by 0.05.

And since is ten years. You just have to calculate 0.05^10

thanks

\(99 \times 99 = (100 -1)(100-1) = 100^2 - 2 \times 100 + 1 = \color{brown}\boxed{9801}\)

The answer would be 2, if you look at the smaller image, then look at the larger and you look at the lengths from both you will see for example the lenght of KJ is 4 and the length of PN is 8. 8 divided by 4 is 2. 

The selling price was not 1.25x or 0.75x, it was the ending cost because if they made "25%" off of one of the gowns, the profit would've been 25$, the starting price wouldn't have been 1.25x... That's a logic flaw...

I would try to generalize the cost of the gowns with a variable, say --- "g"!

A 25% increase is 1.25 (1 + 25/100), so the final cost of one of the gowns would be 1.25g.

A 25% decrease is 0.75 (1 - 25/100), so the final cost of the other gown would be 0.75g.

Adding these two together, it gets 2g, which also happens to be the original cost of both:

Thus, as the result of these transactions, the percentage gain/loss = 0%