I am assuming that the four (or n) points are considered in the order that they appear on the circle rather than the order in which they were chosen. (Otherwise, the quadrilateral [polygon] might not be “proper.”) The event “the polygon contains the center of the circle” is equivalent to the event “every diameter of the circle intersects the polygon,” so it is the complement of the event “all n points fall on one side of some diameter of the circle.” PartyCityFeedback Survey
I see you have asked the same question again.
Please do not do that.
You can make another post just putting a link back to the original question and asking people to answer on the original if you want to.
Guest has put a lot of work into this answers (I have not looked at it myself but at a glance it looks impressive, thanks guest.
Don't you understand the answer given? You were asked for an exact value, not an approximation.
You didn't thank guest for his/her efforts either. Didn't even give him a point.
I know you are a new member so some of these oversites could just be you not understanding how it works. I am sorry if I have sounded to harsh.
Please simplify guests answer and tell us what you get. I want to see if you can do that properly.
For you and others:
You have another answer from asinus here:
https://web2.0calc.com/questions/cos-2-6-where-3-2
I have not looked at either answer.