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(1, 7, 5, 3, 9, 1, 1, 5, 1, 1, 1, 3, 5, 7, 9, 1, 9, 5, 9, 1, 1, 7, 5, 3, 9, 1, 1, 5, 1, 1, 1, 3, 5, 7, 9, 1, 9, 5, 9, 1, 1, 7, 5, 3, 9, 1, 1, 5, 1, 1, 1, 3, 5, 7, 9, 1, 9, 5, 9, 1, 1, 7, 5, 3, 9, 1, 1, 5, 1, 1, 1, 3, 5, 7, 9, 1, 9, 5, 9, 1, 1, 7, 5, 3, 9, 1, 1, 5, 1, 1, 1, 3, 5, 7, 9, 1, 9, 5, 9, 1)>>Total==100 - units digits of the 2 sets.

The probability is: 40 / 100 ==2/5

could that be put in a equation? or inequality

what is it?

Easy. 

When wanting to choose something from a group we use the choose function which states:

n!/r! (n-r)!

So applying this to your problem we get 16!/5!*11!

This simplifies to (16*15*14*13*12) / (5*4*3*2*1)

So the answer should be 4368 if I'm not mistaken.

Is there supposed to be a diagram for this?

Actualy, the smallest possible value of k is 8.

The system reduces to

n = 7 mod 14

n = 6 mod 9

n = 2 mod 25

By the Chinese Remainder Theorem, the smallest four-digit number hat works is 2877.

Solving the system, you get a = 11,  b = 13, c = 12, d = 9, e = 9.  So the answer is 11 + 13 + 12 + 9 + 9 = 54.

The common ratio of the resulting sequence is 2.

The thing is. we cant see what you wrote into the Calculator.

There are 6 ways in which each child can choose a flavor for their scoop of ice cream so that each flavor of ice cream is selected by at least two children: 1. Two children choose each flavor: 6 x 3 = 18 2. Three children choose one flavor, and the other three choose another flavor: 3 x 3 = 9 3. Four children choose one flavor, and the other two choose another flavor: 3 x 2 = 6 4. Five children choose one flavor, and the other one chooses another flavor: 3 x 1 = 3 5. Six children choose one flavor: 3 x 1 = 3 6. Six children choose two flavors: 3 x 2 = 6 Total = 45 ways

The smallest possible value of k is 10.

It is easy to show  x^4+y^4=16  is contained in the circle  x^2+y^2=4*sqrt(2). But x+y=4 is tangent to the circle  x^2+y^2=8 . Since 8 > 4*sqrt(2) , then there is no intersection.

Conclusion: There is no "real solution" to your question, only "imaginary solution"!

There are 740 ways.

The number of integers is 53.

The probability is 35/208

QR = 40/7.