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Well, I do not go to summer camp math classes. 

Bro, where are the numbers?

I suppose this is unsolvable. We can say there are 100 games in total. 75% of it is already finished. That is 75 games. 20% of those game we won. 20% of 75 is 15, so we so far only won 15 games. There are 25 games left, because 100 - 75 is 25. It askes us what percent of the remaining games we need to win in order for our wins to be the same amount as our losses at the end of the season.  We need to win 50 times in total, and we already have 15 wins. The problem is that we only have 25 games left, and 15 + 25 is 40. No matter how many of the remaining games we win, we will not get 50 wins. Therefore, the answer is that there is no solution. 

Of the 40 who had heart trouble, 20 also had high blood pressure, so there are 40-20=20 teachers who only have heart trouble. Similarly, there are 70-20=50 teachers with only high blood pressure. So, of the 120 teachers total, there are 20+20+50 teachers with one of these two. That means 120/90=30 teachers with neither, which is 25% of the teachers.
 

Hi! It looks like you are cheating on your ao ps homework! Please post it on the message board and not here! Thanks!

Its another one of those unsolvable problem id*ots

Eh, summer math camps exist. And different countries have different school systems.

This answer has already been asked. Why do you keep asking this question? There is no solution. You can't go faster and still be late. You should be early. 

Using substitution we can say that x can equal -9sqrt2 as the main goal of using this certain number is to cancel out the 18 as well as making it so that there is a zero that can multiply with 1/sqrt2. 

THUS THE CLOSEST POINT TO ORIGIN IS : (0, -9sqrt2)

The distance between these points (0 , -9sqrt2 ) and (0 , 0 ) will be = 9sqrt2 

Simplify [(a + b^(-1)) (b + c^(-1)) (a^(-1) + c) == (1 + a^(-1)) (1 + b^(-1)) (1 + c^(-1))]

((-1 + a b c) (a + b + c + a b c))/(a b c) == 0

(( -1 +  13) (a + b + c + 13)) / 13 ==0, solve for a + b + c

12/13(a + b +c + 13)==0
Multiply both sides by 13/12

(a + b + c + 13)==0
Subtract 13 from both sides

a + b + c == - 13

abc = 13

(a + 1/b)(b + 1/c)(c + 1/a) = (1 + 1/a)(1 + 1/b)(1 + 1/c)

(ab + 1)(bc + 1)(ca + 1) = (a + 1)(b + 1)(c + 1)

(abc)^2 + abc × (a + b + c) + (ab + bc + ca) + 1

= abc + (ab + bc + ca) + (a + b + c) + 1

(a + b + c) × (13 — 1) = 13 — 13^2

Answer, a + b + c

= 13 × (1 — 13) / (13 — 1)

a + b + c = –13

To be more exact, in another few months. 

Do you have proof that you never made a question. In fact, why do you not blame Melody, Alan, asinus, or admin for being a homework cheater. 

xD😂🤣😂🤣

Also, sorry for the incorrect answer. I forgot how to count. 

Bruh I come from a 2 day trip and this is what I see 😂🤣😂😂

Ok? What's the point?

For the record I have not asked a single homework question on this site..

And even if I were, that does not change the fact that you are a homework cheater. Stop throwing accusations in an attempt to cover up your own failings