Lots of things.
Simple ones you can get from factoring (and also adding the negative sign)
(1,-8), (-1,8), (2, -4) (-2, 4)
More complicated ones
(i, 8i), (2i, 4i) (sqrt8, sqrt8)
(I can't think of anything else)
You didnt specify what you wanted help with, but I assume you would like help simplifying it?
-2(-4x+5)+6x
According to BEDMAS (brackets, exponents, division, multiplication, addition, subtraction), we should first simplify the brackets bit "-2(-4x+5)"
-2(-4x+5)=(-2)*(-4x)+(-2)(5)=8x-10
Now we can add the 6x
So we get the final answer of
8x-10+6x=14x-10
Triangle ABC has vertices A(2, 3),B(1, -8) and C(-3, 2) The line containing the altitude through A intersects the point (0, y). What is the value of y?
Hello Guest!
\(m_{BC}=\frac{y_B-y_C}{x_B-x_C}=\frac{-8-2}{1-(-3)}=-\frac{10}{4}=-\frac{5}{2}\\ m_{h_A}=-\frac{1}{m_{BC}}=\frac{2}{5}\\ f_{h_A}(x)=m_{h_a}(x-x_A)+y_A\\ f_{h_A}(x)=\frac{2}{5}x-\frac{4}{5}+3\\ f_{h_A}(x)=\frac{2}{5}x\color{blue}+\frac{11}{5}\)
The value of y is \(\color{blue}\frac{11}{5}\).
!
\(t\in \{0,7,12,15,16\}\\ {\color{blue}The\ average}\ of\ all\ distinct\ possible values\ of\ t\ \color{blue}is\ \frac{50}{5}=10.\)
Let the original rectangular solid be ABCD, and let the points where the cuts are made be E, F, and G. Then, EFGH is a square with side length 2, and ABCD is divided into 8 congruent smaller cubes. The shaded piece is made up of the four corner cubes, which have a total volume of 4*(1^3)=4 cubic inches.
For the record, Post #2, signed by GA, is not by the real GA.
jlunn762, keep your moronic video uploads for your personal use. Your imbecility and lack of common sense is astounding, but not surprising considering that kind of bullshit is your form of entertainment.
GA
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\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
https://youtu.be/exQS9cLK-ok?si=PlZPwGtqpujj32Xb
I'm pretty sure GA is just convinced that I am downvoting her posts and taking the opportunity to express her displeasure.
GA called you and idiot LOL
This idiot forgot to copy the diagram from their homework lol! Such a bad homework cheater.
We have that x−3=7a and y+3=7b for some integers a and b. Then \begin{align*} x^2+xy+y^2+n &= (x-3)^2 + 2(x-3)(y+3) + (y+3)^2 + n \ &= 49a^2 + 2(7a)(7b) + 49b^2 + n \ &= 49(a^2+7ab+b^2) + n \ &\equiv n \pmod{7}. \end{align*}Since n is a multiple of 7, the smallest positive integer n such that x2+xy+y2+n is a multiple of 7 is 7.
0.82-0.03=0.79
Your threats are empty and unecessary, but if you insist that you are The0neXWZ please login and send me a private message.
AI really is amazing, given an incomplete problem it can hallucinate an entire solution!
What the f*ck do you think you're doing, you motherf*cker? I'll have you know I'm The0neXWZ, if you don't watch your goddamn mouth.
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