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The area of the curve is approximately 25/3.

There were 78 marbles originally in the bag.

Answer: The baker should buy a minimum of 14 cups of flour and a maximum of 34 cups of flour.

The correct answer is

C.

90 ≥ 2x + 44 ≤ 95

The solution is x >= 3.

The solution is x >= 4.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

The area of trapezoid PQRS is 18.

We know that the interior angle measure of an equilateral triangle is 60 degrees, and the interior angle measure of a regular dodecagon is 150 degrees. Summing it up, we have 210 degrees. Because 360 degrees surround a point, the regular n-gon must have 150 as it's interior angle measure. A dodecagonn would work, so n = 12.

The area of trapezoid PQRS is 18.

We can first find the area of a hexagon. If we break it into 6 equilateral triangles, we can calculate their areas. Let's say the side length of the regular hexagon is \(s.\) The area of one of the equilateral triangle is \(\frac{s^2 \sqrt{3}}{4}\), so the area of the entife hexagon is \(\frac{3s^2 \sqrt{3}}{2}.\) Because we know the area is 3, we can solve for s:

\(\frac{3s^2 \sqrt{3}}{2} = 3 \) ==> \(3 s^2 \sqrt{3} = 6\) ==> \(s^2 \sqrt{3} = 2\) ==> \(3 s^2 = 2 \sqrt{3} \) ==> \(s^2 = \frac{2 \sqrt{3}}{3}\)

This is best I can go. It get's really complicated if you go even further. Please let me know if I made a mistake.

Let's analyze the equations one by one:

A + B = C: This tells us that C must be greater than both A and B.

AA - B = 2C: This equation can be rewritten as 10A + A - B = 2C, or 11A - B = 2C. Since C is greater than A and B, 2C must be greater than 11A.

This is only possible if A is a very small number.

C * B = AA + A: This equation can be rewritten as CB = 11A. Since 11A is a multiple of 11, CB must also be a multiple of 11.

Considering these three equations, we can deduce the following:

A must be 1: This is the only way to satisfy the second equation, 11A - B = 2C, with C being greater than A and B.

C must be 3: Since A is 1, the first equation becomes 1 + B = C. The only way to satisfy this with C being greater than B is if C is 3.

B must be 2: From the first equation, if A is 1 and C is 3, then B must be 2.

Therefore, A + B + C = 1 + 2 + 3 = 6.

The area of trapezoid PQRS is 18.