All Answers 358662 Answers

The answer is 12.

The answer is 100/11.

The answer is 10/3.

The domain is (-inf, 4) u (5,inf).

The answer is 5.

The answer is 12.

A jet climbs at a steady rate at an angle of 0.5 during take-off.     

What will its height be after a 2.2-km initial ascent at this angle?      

Is the 2.2 km (1) the air distance of the path the plane flew,     

           or is it (2) the ground distance below the plane's path?     

(1)    h / 2.2  =  sin(0.5^o)     

        h / 2.2  =  0.008726535     

                h  =  (2.2)(0.008726535)     

                h  =  0.019198378 km     

(2)    h / 2.2  =  tan(0.5^o)     

        h / 2.2  =  0.008726867     

                h  =  (2.2)(0.008726867)     

                h  =  0.019199109 km     

                height rounds to 19.2 meters either way     

_.     

f(x) = 2x + 8 if 1 \le x \le 2

f(x) = 13 - 5x if 2 < x \le 3

f(x) = 20 - 14x if 3 < x \le 4

f(x) = 40 + 5x if 4 < x \le 5

x= 2x + 8                 x = 13 - 5x                   x = 20 - 14x                 x  = 40 + 5x

-x = 8                      6x  = 13                       15x = 20                       -4x  =  40

x = -8                      x = 13/6                         x = 20 / 15  = 4/3        x = -10 

-8 not in interval      13/6 in the interval        4/3 not in interval       -10 not in interval

Answer :   13 / 6

Top rectangle = 6 * 2  =12

Rectangle directly below this = 6 * 1  = 6

Right triangle on the left = (1/2)(3)(3)  = 4.5

Middle rectangle = 6 * 2 = 12

Rectangle below this = 6 * 2 = 12

Half-circle with radius of 5  =  (1/2) pi * (5^2)  = 12.5 pi

Total area =  [ 12 + 6 + 4.5+ 12 + 12 + 12.5 pi ]  cm^2  = 85.77 cm^2

Kim made soup which contains 75 total ounces of beans. The soup has 2 kinds of beans, black and red. There are 4 times as many ounces of black beans as red beans. How many ounces of red beans are in the soup?     

   RB + BB  =  75     

            BB  =  4 • RB     

   RB + BB  =  75     

   RB + 4RB  =  75     

            5RB  =  75     

              RB  =  15     

_.     

The sum of the interior angles of a pentagon is:

(5−2)×180=540∘(5 - 2)\times 180 = 540^\circ(5−2)×180=540∘

Given that ∠A=∠B=90∘\angle A = \angle B = 90^\circ∠A=∠B=90∘, we have:

A+B+C+D+E=540∘A + B + C + D + E = 540^\circA+B+C+D+E=540∘ 90+90+C+D+E=540⇒C+D+E=360∘90 + 90 + C + D + E = 540 \Rightarrow C + D + E = 360^\circ90+90+C+D+E=540⇒C+D+E=360∘

Since the pentagon is equilateral and symmetric (with AAA and BBB equal and adjacent), we can infer:

C=EC = EC=E

Let C=E=xC = E = xC=E=x and D=yD = yD=y. Then:

2x+y=3602x + y = 3602x+y=360

Because the pentagon is concave, one interior angle must be greater than 180∘180^\circ180∘, which is DDD. From geometric reasoning, the valid solution is:

x=135∘,y=90∘x = 135^\circ,\quad y = 90^\circx=135∘,y=90∘

Therefore:

∠E=135∘\angle E = 135^\circ∠E=135∘

Answer: 135∘135^\circ135∘

what is the area of this figure     

EF = 12 / sqrt(2) = 8.4853     

Triangle EBF = (1/2) • (8.4853) • (8.4853)  =  36.0002     

Triangle EBA    same way                           =  36.0002     

Triangle CBF    same way                           =  36.0002     

DF / EF = cotangent(30^o) = 1.7321     

DF = (8.4853) • (1.7321) = 14.6974     

Triangle EFD = (1/2) • (14.6974) • (8.4853)  =  62.3559     

Triangle CFD    same way                             =  62.3559     

total of all five triangles                                    232.7124     

_.     

   Hi Can anyone help me I need to draw circle with raduis of 1.8 cm     

   Do you mean the formula for a circle on the Cartesian Plane?     

   (x – h) + (y – k)  =  r²     where (h,k) is the center and r is the radius     

_.     

   The surface area of a sphere with a diameter of 12 units is:     

            A_sphere = 4 π r²     

            A  =  4 • 3.1416 • 6²     

            A  =  452.39     

            This relates to  B) . . . they just used 3.14 instead of 3.1416.     

_.