All Answers 358094 Answers

$${\mathtt{2.9}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{8}}} = {\mathtt{290\,000\,000}}$$

2.9x 10^8

Your welcome haha

Its my sister she just joined right now

what?

HAHA                     

HAHA gummy love it

13 / 25 = x / 100     cross-multiply

1300 = 25x           divide by 25

52 = x = 52%

I wish I had friends to tell me if I smelled nice or not today.... 

thank you!

It would help if you spoke in english not french.

You would have a dead lobster soon 

or

A ROCKLOBSTER

Love that song. LOL!

Now it's going to be stuck in my head thanks anon.

Any positive number (except 1) could - theoretically - be used as a base.....but 10 and "e" are the most common....

Wow.....thanks h7....I didn't even know you could do that on this calculator!!....did you figure that out just fooling around with it ????

i already worked it out in my head trololol!

x=-2y-3

4y-x=9

Notice that we can substitute the first thing into the second....this gives

4x - (-2y - 3) = 9    simplify

6y + 3 = 9      subtract 3 from both sides

6y = 6            divide both sides by 6

y = 1       and subtituting this back into x = -2y - 3 ,  we find that x = -2(1) - 3   = -5

So our answer is x = -5 and y =1

What's your worstb kick name

NO 

I-I-I can't.

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{x, y}}}}}{{solve}}{\left(\begin{array}{l}{\mathtt{x}}={\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{3}}\\
{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{x}}={\mathtt{9}}\end{array}\right)} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{5}}\\
{\mathtt{y}} = {\mathtt{1}}\\
\end{array} \right\}$$

Tommy Tucker's toy twisted and turned into the tornado

You aleady have it in scientific notation.....

It's not that bad

Well....do I feel sorry for you.LOL!

$${factor}{\left({\mathtt{8\,820}}\right)} = {{\mathtt{2}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{{\mathtt{3}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}{{\mathtt{7}}}^{{\mathtt{2}}}$$

I forgot it you haveto rewrite