All Answers 358089 Answers

Distributive Property is exactly what it sounds. When you distribute something, you're giving equal quantities to all parties, right? The same applies to mathematics. You're multiplying, or "distributing," one factor amongst another factor, or set of factors.

$$4(x + 2) \Rightarrow 4x + 8$$

$$3(x + 3) \Rightarrow 3x + 9$$

$$(x + 2)(x + 2) \Rightarrow x^2 + 2x + 2x + 4 \Rightarrow x^2 + 4x + 4$$

You can use the distributive property by distributing....the number...

ex. a(b+c)

You multiply a by b (ab)

You then multiply a by c (ac)

I would take the 17 cookies (now taking one for the original owner) leaving 16 (ignoring the half for now), divide that by 4 which gives you 4 itself and 4 divided in half is 2, that gives every child 2 cookies except for the original owner ( still one cookie even).  Now takethe 1/2 and dived that with 4 and that leaves .6, that means that each kid gets 2.6 cookies while leaving the original owner with one cookie. 

Think of it as a product rather than a quotient. 

$${\frac{\left({\frac{{\mathtt{53}}}{{\mathtt{552}}}}\right)}{{\mathtt{100}}}} = \left({\frac{{\mathtt{53}}}{{\mathtt{552}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{100}}}}\right)$$

Which gives us a final fraction of:  $$\left({\frac{{\mathtt{53}}}{{\mathtt{55\,200}}}}\right)$$

Very detailed answer hahaha, I HAVEEEEEEEEEE

Scientific Notation is just moving decimals around while maintaining the consistency of the number. It's manipulating large or small numbers with powers of ten. Multiplying a number by ten shifts a decimal place to the right, similarly dividing shifts a decimal place to the left. 

$${\mathtt{24.91}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{1}}} = {\mathtt{249.1}}$$ 

$${\mathtt{24.91}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{0}}} = {\mathtt{24.91}}$$

$${\mathtt{24.91}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{1}}} = {\mathtt{2.491}}$$

To know which way to shift the decimal is solely reliant on the power of ten. 

$${\mathtt{1}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{X}}}$$

Should X be positive then the decimal will shift X places to the right, otherwise X is negative and should be shifted X places to the left. 

Hope this helps. 

Nauseated it's not really real, it's a math word problem. Math word problems are not real. They are just fake sentences but seem real.

Nauseated stop being mean I don't have a disease, my teacher is not lying, and I'm not dumb

x = 20.148148148148....

so by multiplying by 1000 we can move the decimal point to again get that exact fraction part

1000x = 20148.148148148.....

1x = 20.148148148....

subtraction of the last two lines gives us the value for 999x,

999x = 20128 exactly!

Can you finish the final little step now?

Pull the 6th root 6:

sqrt6(1.7715690000000003301)

You could first take the square root of the number, then take the cube root of that.

Or you could use a calculator that allows you to take any power, here you'll take the number to the power 0.16666667  because that is the decimal value of 1/6, at least approximately.

Or you could use logarithms.

BTW, your number has the commas in the wrong places, or maybe there's a digit has gone missing?  🐾

just hit a b c.

its 16.13

$${{\mathtt{38\,982}}}^{{\mathtt{30}}} = {\mathtt{532\,014\,555\,570\,033\,465\,011\,701\,095\,266\,685\,794\,329\,592\,219\,176\,345\,944\,073\,107\,735\,843\,088\,718\,706\,969\,865\,925\,171\,384\,581\,306\,374\,222\,577\,554\,877\,567\,435\,961\,085\,094\,566\,637\,338\,624}}$$

the answer is 0.096

We have this....10% off of something is just 90% of its valued = .90 .....thus.....

520 =  1300(.90)ⁿ   where n is the number of years

Divide both sides by 1300

520/1300  = (.90)ⁿ       take the log of both sides

log(520 / 1300) = log(.90)ⁿ     and by a log property, we can write

log(520 / 1300) = n log (.90)       divide both sides by log(.90)

log(520 / 1300) / log(.90)  = n = about 8.7 years

No....I just answered.....I don't know what this calc can do......now you know!

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{x, y}}}}}{{solve}}{\left(\begin{array}{l}{\mathtt{x}}={\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{3}}\\
{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{x}}={\mathtt{9}}\end{array}\right)} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{5}}\\
{\mathtt{y}} = {\mathtt{1}}\\
\end{array} \right\}$$!

It is a word.  It isn't racist

I don't know.

Is it?

LOL!!!

$${\sqrt{{\mathtt{13}}}} = {\mathtt{3.605\: \!551\: \!275\: \!463\: \!989\: \!3}}$$

$${\mathtt{10}}{\mathtt{\,\times\,}}{log}_{10}\left({\frac{{\mathtt{4.3}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{7}}}}{{{\mathtt{10}}}^{-{\mathtt{12}}}}}\right) = {\mathtt{196.334\: \!684\: \!555\: \!795\: \!85}}$$

785.389163397448 (for real)

$${\sqrt{{\mathtt{644}}}} = {\mathtt{25.377\: \!155\: \!080\: \!899\: \!040\: \!8}}$$

Uh... 2. Why would you ask that?