46..........................

47...........................

What is this about?

$${\mathtt{6}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}{\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{y}}\right) = {\mathtt{19}} \Rightarrow {\mathtt{y}} = {\mathtt{\,-\,}}{\frac{{\mathtt{25}}}{{\mathtt{6}}}} \Rightarrow {\mathtt{y}} = -{\mathtt{4.166\: \!666\: \!666\: \!666\: \!666\: \!7}}$$

$${\frac{\left({\frac{{\mathtt{14}}}{{\mathtt{9}}}}\right)}{\left({\frac{{\mathtt{11}}}{{\mathtt{9}}}}\right)}} = {\frac{{\mathtt{14}}}{{\mathtt{11}}}} = {\mathtt{1.272\: \!727\: \!272\: \!727\: \!272\: \!7}}$$

$${\mathtt{93}}{\mathtt{\,\times\,}}{\mathtt{97}} = {\mathtt{9\,021}}$$

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Answer!!!!!!!!!!!!!!!

$${\frac{{\mathtt{12}}}{\left({\frac{{\mathtt{5}}}{{\mathtt{3}}}}\right)}} = {\frac{{\mathtt{36}}}{{\mathtt{5}}}} = {\mathtt{7.2}}$$

IT'S LIKE YOUR CRAZYMUUSTACHE9418!!!

What is up with the caps and emoticons??

Or basically the Reeses....wouldn't be a Reeses

2) Reeses need peanut butter

1) Cookies need chocolate (unless snickerdoodle)

But Brittney is right about two things

Hey chocolate is good

On B, mass A is applying a force that is trying to pull B to the left.  This is balanced by the pull from the sloping string over the pulley, which has a horizontal component of Tsin(40°).  Because the system is stationary, the pull to the left must have the same magnitude as the pull to the right.  (Note: the vertical component of the pull from the sloping string exactly balances the weight of B).

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Search it up on the Internet

Disgusting and disturbing!!!  Ewwww!!!

Ewwwwwwwww

Ewwwwwwwwww

Ewwwww....I'll say it

It probably would!!!