To prove that, in congruent triangles, the bisectors of congruent angles are themselves congruent segments.
Let ABC and DEF be congruent triangles
And let CC' be the angle bisector of of angle C ....and let FF' be the angle bisector of F
Then, since angle C = angle F, then the bisected angles BCC' and EFF' will also be equal.
And BC = EF. And angle B = angle E.
Thus, by ASA, triangle BCC' = triangle EFF'.
Thus, the angle bisectors (segments) CC' and FF' are equal
(I think this is something on the order of what you might need...I hope)
