Factors of 16 included:1,2,4,8,16

16/1=16

16/2=8

16/4=4

16/8=2

16/16=1

Yeah you are both right but I do like Happy's working better.

This is because you are finding   8% of 5 and i think it is best to change the words into a number sentence as precisely as possible.

Now 8% is 8/100  (or 0.08)   and 'of' means multiply.  So the question becomes

8/100 * 5

you are both right though :))

$$\\(6j^{-2})^{-3}\\
=6^{-3}\;\;j^{-2*-3}\\\\
=\frac{6^{-3}\;\;j^{6}}{1}\\\\
=\frac{j^{6}}{6^3}\\\\
=\frac{j^{6}}{216}\\\\
$Now if j is an ordinary pronumeral then the question is finished$\\
$but if j is the imaginary number $ \sqrt{-1} \qquad then\\\\
(\sqrt{-1})^6=((\sqrt{-1})^2)^3=(-1)^3=-1\\\\
$ so the final answer would be $
\frac{-1}{216}$$

Yeah..... 

Correct....she's a little "picky" about work....might learn that now

So was I right or wrong

You do this

0.08*5=0.4

Like Alexa said

For percent,  you do this

If the number has tens, like 11,  then the decimal is 0.11

If it is only ones,  like 8,  then it is 0.08

And if it is hundreds or bigger,  like 747,  then it is 7.47

Oh ok well this is how I did it...: first I divided 5 by 100 which equals 0.05 then I multiplied 0.05 by 8 and got 0.4! 

you can't 'solve' it - it is not equal to anything.  

-32+73=41

41+(-50)=-9

-9 is the answer

Please show how to get the answer Alex. 

Otherwise the asker can't learn anything. :)

Oh no sweat

the strongest color is blue that why wee see the sky blue

do you mean - if this is what you meant then you needed to use bracketsaround the (x+6)

$$e^{x+6}=1$$

any number raised to the power of 0 is equal to 1

x+6=0

x=-6

Okay thanks so much!

There's a trigonometric identity that this resembles.

1 = sin^2+cos^2

Basically, ? = cos^2

$$cos^2x$$

You need to memorize this it is a very important identity 

$$sin^2x+cos^2x=1$$

like terms are terms that you are allowed to add or subtract together.  

They must have the same letter and those letters must be raised to the same powers.

It is easiest to think of the letters as things (just for add and subtract - doesn't work the same for mult or divide)

-------------------------------------------------------------------

ex

3C+8B-C+6d

you could think of this as

=3cats + 8bananas - a cat +6dogs

=3cats + 8bananas - 1cat +6dogs        (a cat is the same as 1 cat)

now the cats are like terms - I can put those together   (3cats)+(-1cat) = 2cats   

note that the minus sign always belongs to the term following it.

so now we have

=2cats + 8bananas +6dogs 

The other things are all different - they are unlike terms - so the simplification is finished.

=2C + 8B + 6D

------------------------------------------------------------

5mt + 8t - m +10tm + 2t^2m

The only terms here with exactly the same letters raised to exactly the same powers is 5mt and 10tm.

It doesn't matterthat the letters are in a different order because

10tm=10*t*m=10*m*t=10mt

5mt+10tm=15mt  (or    15tm)

so the answer is

15mt + 8t - m + 2t^2m

It cannot be simplified further because there are no more like terms.    

------------------------------------------------------------

Okay thanks Melody and Happy7 you both helped me a lot!

I need to buy 3 things and the shopping total needs to be less than or equal to $5 because that is all the money that I have.

$$a+b+c\le\;5$$

√ = square root.

0.4 I believe

Okay thanks and would I use them in the real world like when I go shopping for food?

An inequalitie is when two numbers aren't equal,  or two equations.

They are the solutions to the 12th order polynomial x¹² = 1

A 12th order polynomial has exactly 12 roots.

They can be pictured as equally spaced points on the unit circle in the complex plane.

Each root is separated from the next by an angle of 360/12 = 30 degrees.

Starting with the obvious root x = 1 + 0i  on the x-axis, the next one (in a clockwise direction) has coordinates x = cos(30) and y = sin(30) (because the radius of the unit circle is 1, by definition!).  cos(30) = (√3)/2 and sin(30) = 1/2 so this point can be represented by the complex value (√3)/2 + i(1/2).

Just work your way around the unit circle in a similar manner for the others.

.