All Answers 358927 Answers

If the probability of a single driver wearing a seatbelt is 0.8, then the probability of k out of 700 drivers wearing their seat belts is:

$$0.8^k0.2^{700-k}nCr(700,k)$$

where the last term is the number of ways of choosing groups of size k from 700.  To answer the question here we need to sum this from k = 538 to k=546:

$$\sum_{k=538}^{546}0.8^k0.2^{700-k}nCr(700.k) = 0.084$$

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Wallah!sir Albert is here!who dropped you...the angels....what are you wearing...a white gown?????

look rosala, the president of your desciples has made you proud dear sir!

i shall be rewarded!

(best player on this forum ;)

dad 123456

I remember you Rosala. You were the inspiration for the E in Energy.

The inspiration continues to this day.

2210000000000000

I thought you don't do fair!

$${\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{12}}$$

So we will do this like !

y +1 = 1/2(x+2)

now first we will multiply 2 by x and 2 

Y + 1 = 1/2x + 4

now we will cross multiply this!

(y+1)(2x+4)=1

now we will multiply these  too!

2xy + 4y + 2x + 4 = 1

now thats how I solved it! Lets see what answer do our other friends come up with!

Need full solution

$$\\ \small{\text{
$
\dfrac{ \left( \sqrt{3}-2\sqrt{5}\right ) \left( 2\sqrt{5}+\sqrt{3} \right) }{17\sqrt{20}}
$
}}$\\\\$
\small{\text{
$
=\dfrac{ \left( \sqrt{3}-2\sqrt{5}\right ) \left( \sqrt{3}+ 2\sqrt{5} \right) }{17\sqrt{20}} \quad |\quad (a-b)(a+b) = a^2-b^2 \quad \left( \sqrt{3}-2\sqrt{5}\right ) \left( \sqrt{3}+ 2\sqrt{5} \right) = 3-4*5
$
}}$\\\\$
\small{\text{
$
=\dfrac{ 3-4*5 }{17\sqrt{20}} $
}}$\\\\$
\small{\text{
$
=\dfrac{ -17 }{17\sqrt{20}} $
}}$\\\\$
\small{\text{
$
=-\dfrac{ 1 }{\sqrt{20}} \quad | \quad * \frac{\sqrt{20}} {\sqrt{20} } $
}}$\\\\$
\small{\text{
$
=-\dfrac{\sqrt{20} }{20} $
}}$\\\\$
\small{\text{
$
=-\dfrac{\sqrt{4*5} }{20} $
}}$\\\\$
\small{\text{
$
=-\dfrac{\sqrt{4}*\sqrt{5} } {20} $
}}$\\\\$
\small{\text{
$
=-\dfrac{2\sqrt{5} } {20} $
}}$\\\\$
\small{\text{
$
=-\dfrac{\sqrt{5} } {10} $
}}$$

^Try making the mixed number improper fraction

(3x-2)(4x+3)-(x+3)(2x-5)=(2x+1)(5x-2)

$$\\\small{\text{
$
(3x-2)(4x+3) - (x+3)(2x-5) =(2x+1)(5x-2) \quad | \quad +(x+3)(2x-5)\\
$
}}$\\$
\small{\text{
$
(3x-2)(4x+3) =(2x+1)(5x-2) + (x+3)(2x-5)
$
}}$\\$
\small{\text{
$
12x^2 +9x -8x -6 = 10x^2 -4x +5x -2 + 2x^2 -5x +6x -15$
}}$\\$
\small{\text{
$
\underbrace{12x^2 -10x^2- 2x^2}_{0} \underbrace{+9x -8x +4x -5x +5x -6x}_{-x} \underbrace{-6 +2 +15}_{11} = 0 $
}}$\\\\$
\small{\text{
$
-x +11 = 0\\
$
}}$\\$
\small{\text{
$
x=11$
}}$$

Since 48 is the half of 96,  the taxed price of the 48ft building is the half of the 96ft building's taxed price. 

Solution:

3.6+3.6= 7.2 , 7.2-6.1= 1.1 ..... = the tax is ¥1.1m

The problem is, when I try to enter 2 3/4 it wants to read 23/4 and it won't let me put a space between the numbers to distinguish it's not 23.

=Your a zombiee

i dont know

|Whole number| f1/f2

EX: 24 3/4 x 45 1/2=

- 1 2/3, 2 1/3, 5 3/4, 7 6/10

height: 8.4 diameter: 3.5 find the volume

$$\small{\text{
$
\begin{array}{rcl}
$ Volume $ = v &=& \pi*(\frac{d}{2})^2*h \\
v & = & 3.141592654 * 4.2^2 * 3.5 \\
v & = & 193.962 $ units $
\end{array}
$
}}$$

3ⁿ ends with a 1 in the units place whenever n is a multiple of 4, so both 3²⁰⁰⁰ and 3³⁶ end with a 1. So a = 1 and b = 9, hence a + b = 10

.

what is b squared plus b squared

$$\\ \small{\text{
I.
$
b^2+b^2=b^2(1+1)=b^2*2= 2*b^2
$
}}$\\$
\small{\text{
II.
$
b^2+b^2=b*(b+b)=b*(2*b)= 2*b^2
$
}}$$

i am a desciple of Dr.Albert Einstein so according to him 1+1 is 2 ......i am sorry but i follow the 2.......you can arrange a debate for it.....all my desciple friends would join!:)

Thats good anonymous, i wish i had a wand that could post an answer to this!

sorry for we couldnt offer you any help!but thats very rare!

glad you got the answer!

Sasini's answer would be correct if the question involved t^2.  However, it has 2^t, so the only way this could be zero is if t is minus infinity.

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a = 4,  b = 100

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The calculator in Microsoft Windows can deal with gradians:

For those who haven't heard of grads, there are 400 of them in a complete circle (so you could work out the answer in degrees and multiply the result by 400/360 if your calculator doesn't have grads).

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$$(\sqrt3-2\sqrt5)(2\sqrt5 +\sqrt3)=3-4\times 5=-17$$

$$\frac{1}{\sqrt20}=\frac{\sqrt20}{20}=\frac{2\sqrt5}{20}=\frac{\sqrt5}{10}$$

So:

$$\frac{(\sqrt3 - 2\sqrt5)(2\sqrt5 + \sqrt3)}{17\sqrt20}=\frac{-17\sqrt5}{17\times10}=-\frac{\sqrt5}{10}$$

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