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Two fractions that are on the same denominator are called like fractions.

It is easy to add or subtract like fractions. If we add like fractions we just add the numerators and this sum will be the new numerator while the denominator is stays the same.

Example:

Factors that are not on the same denominator are called unlike fractions. To find the sum or the difference of unlike fractions we need to find a common denominator, the least common denominator - LCD.

To find the common denominator we multiply the first fraction by the denominator of the second fraction.

Example:

You can rewrite fractions into decimal numbers by using long division.

Example:

Rewrite 2/4 as decimals.

This means that 2/4 is equal to 0.5. Decimals like 0.5 are called terminating decimals.

Example:

Rewrite 2/3 as decimals.

3 is not a factor of 2. 3 is not a factor of 20 but a factor of 18 which gives us a remainder of 2.

When you multiply fractions, the numerators will be multiplied with each other and the denominators will be multiplied with each other.

Example:

When you are dividing fractions, you are going to multiply the first fraction by the multiplicative inverse of the second fraction.

Example:

That is easy to answer.

1. convert the mixed numbers into fractions
2. use the algebraic formula for multiplying fractions
3. for example 1 2/6 by 2 1/4
4. 1 2/6 * 2 1/4 = 8/6 9/4= 8/9*6/4= 72/24
5. reduce fractions so we get 4/1 and simplifying 4

" f(x) = -2 "  just means that the function equals -2 no matter what x is. 

I'm not sure I understand your question ?

Least Common Multiples(LCM)  ?

A. 23^31,23^17

$$\small{ \begin{array}{l|rclclclcl} \text{Number 1:} & 23^{31} &=& 23^{\textcolor[rgb]{1,0,0}{31}} &&&&&& \\
\text{Number 2:} & 23^{17} &=& 23^{17} &&&&&&\\
\hline \text{The greatest Exponent} \\ \text{ of each prime number} &\text{LCM}&=& 23^{\textcolor[rgb]{1,0,0}{31}}&&&&&&
\end{array} }}$$

B. 3^7*5^3*7^3,2^11*3^5*5^9

$$\small{
\begin{array}{l|rclclclcl}
\text{Number 1:} & 3^{7}*5^3*7^3 &=& 2^0 &*& 3^{\textcolor[rgb]{1,0,0}{7}} &*& 5^3 &*& 7^{\textcolor[rgb]{1,0,0}{3}} \\
\text{Number 2:} & 2^{11}*3^5*5^9 &=& 2^{\textcolor[rgb]{1,0,0}{11}}&*& 3^5 &*& 5^{\textcolor[rgb]{1,0,0}{9}} &*& 7^0\\ \hline
\text{The greatest Exponent}
\\ \text{ of each prime number} &\text{LCM}&=& 2^{\textcolor[rgb]{1,0,0}{11}}&*&3^{\textcolor[rgb]{1,0,0}{7}} &*&5^{\textcolor[rgb]{1,0,0}{9}} &*& 7^{\textcolor[rgb]{1,0,0}{3}}
\end{array}
}}$$

C. 3^13*5^17,2^12*7^21

  $$\small{
\begin{array}{l|rclclclcl}
\text{Number 1:} & 3^{13}*5^{17} &=& 2^0 &*& 3^{\textcolor[rgb]{1,0,0}{13}} &*& 5^{\textcolor[rgb]{1,0,0}{17}} &*& 7^0 \\
\text{Number 2:} & 2^{12}*7^{21} &=& 2^{\textcolor[rgb]{1,0,0}{12}}&*& 3^0 &*& 5^0 &*& 7^{\textcolor[rgb]{1,0,0}{21}}\\ \hline
\text{The greatest Exponent}
\\ \text{ of each prime number} &\text{LCM}&=& 2^{\textcolor[rgb]{1,0,0}{12}}&*&3^{\textcolor[rgb]{1,0,0}{13}} &*&5^{\textcolor[rgb]{1,0,0}{17}} &*& 7^{\textcolor[rgb]{1,0,0}{21}}
\end{array}
}}$$ 

According to Wikipedia.....

I'll do "A".....the other two are solved exactly the same way.....!!!!

-2.3+m=7     add   2.3 to both sides

m = 9.3

Yeah, or ten-ty-one or something like that :)

I guess our close ancestors wanted the small natural numbers (positive integers) to have their own unique names. 

I've heard a story onece about a child who learned to count, he said:

" ... sixteen, seventeen, eighteen, nineteen, tenteen, eleventeen, twelveteen, thirteen... WHAT ?"

There's nothing to "solve" here

It's like asking to "solve"  cos(20x) .....!!!

Besides, "solving" usually means actually having an equation....which we don't in this case......

It is not an equation because there is no equal sign.  So you definitely cannot solve it.

This question is unanswerable....it could have been at many different heights....!!!

thank you

Refer to this one that Tetration and I just did

http://web2.0calc.com/questions/a-number-minus-3-is-8

Here's B

3^7*5^3*7^3, 2^11*3^5*5^9

We take each different base along with the highest power associated with that base.....so we have....

2^11 x 3^7 x 5*9 x 7^3 = LCM = 3,000,564,000,000,000

Here is another way to look at it.    

What take away 3 will land you at -8 ?

Call the amount of money before the depisit x. Then 500$ is added. Now you have $4,732. Can you take over from here?

Is it reasonable? $4,732 ≈ 5 000$, right? And you add just 500$. That tells you that the original amount of money must have been quiet ...

Let W be the original weight.

So we have

W - 45 = 67      add 45 to both sides

W = 112 carats

Thanks guys!  This is very helpful.

--CG

I agree with Melody. Just rename "a number" "x", set up what it equals, and add (plus) or subtract (minus) the same value on both sides of the equality sign (=). 

Have a go! We'll help you if you get stuck. Or read my answer on "A number minus 3 is -8".

Come on Rochelle, you can at least guess at the answer.  

Then we can look at your guess if you want us to.

You would learn better that way too.   

"something" - 3 "is" -8

Rename "something" "x". Realise the "is" means "is equal to" or "=".

x - 3 = -8    Add 3 to both sides:

x = - 8 + 3 = -5

You can try the last one for yourself anon unless one of the others on the forum would like to have a go.

And I am not meaning our other full blown mathematicians either.

Why don't one of you amateurs have a go at it?

Don't forget to show your logic though  

Please rephrase the question to make it easier to understand?

Thanks anon.    I messed up   LOL

the first one 

LCM=  23^31 because they both go into that. 

2)

$$\\3^7*5^3*7^3\quad and \quad 2^{11}*3^5*5^9\\\\
3^7*5^3*7^3=3^5*3^2*5^3*7^3\\
3^7*5^3*7^3=\textcolor[rgb]{0,1,0}{3^5*5^3}*7^3*3^2\\\\
2^{11}*3^5*5^9=\textcolor[rgb]{0,1,0}{3^5*5^3}*5^6*2^{11}\\\\
$So the lowest common multiple will be $\\
\textcolor[rgb]{0,1,0}{3^5*5^3}*7^3*3^2*5^6*2^{11}$$

B.

$$\\3^7*5^3*7^3\quad and \quad 2^{11}*3^5*5^9\\\\
3^7*5^3*7^3=3^5*3^2*5^3*7^3\\
3^7*5^3*7^3=\textcolor[rgb]{0,1,0}{3^5*5^3}*7^3*3^2\\\\
2^{11}*3^5*5^9=\textcolor[rgb]{0,1,0}{3^5*5^3}*5^6*2^{11}\\\\
$So the lowest common denominator is $\textcolor[rgb]{0,1,0}{3^5*5^3}$$

miss melody he is looking for LCM not LCD :)