All Answers 358468 Answers

2(7 1/4)=6(1 3/4)+4

7 + 1/4 =  29/4      and   1 + 3/4  = 7/4

So

2(29/4) = 6(7/4) + 4

58/4  = 42/4 + 16/4

58/4  = 58/4

And this is true....

I assume you want the area.....

The area is given by s^2, where s is the side length...

So

A = (9.3cm)^2      and you can evaluate this on your calculator....

I don't see anything, but here's the equation...

y = 10 + .25x   where x is the number of seconds and "y' is the number of gallons after "x"  seconds....

I do not run to references Chris.

I just work it out myself.  It is easy after you  have done it a few times.

I'm afraid I have to run for the references whenever I have to use this too, Melody.....

It IS a pretty neat how it wotks, though.....and the concept is simple.....!!!

 "Benford's Law" is the basic premise that, in many statistical data sets, numbers with leading "1s" tend to occur more often than numbers with leading "2s"....and numbers with leading "2s" tend to occur more often that numbers with leading "3s," etc.

This is yet another formula that I have not memorised.  

I work it out every time.

(This is not presenting properly as fractions because LaTex is playing up!)

$$\\\mbox{Consider the red tangent. }\\
$The gradient of this line is f'(x_0)$\\
BUT \mbox{ The tangent is also } \\\\
=rise/run\\\\
=(f(x_0)-0)/(x_0-x_1)\\\\
=f(x_0)/(x_0-x_1)\\\\\\\\
f'(x_0)=f(x_0)/(x_0-x_1)\\\\
f'(x_0)(x_0-x_1)=f(x_0)\\\\
(x_0-x_1)=f(x_0)/f'(x)\\\\
-x_1=[f(x_0)/f'(x_0)]-x_0\\\\
x_1=x_0-[f(x_0)/f'(x)]\\\\$$

Hi Tenacious,

I cannot remember what factorising questions I gave you - maybe they were too hard.

Maybe you could try these.  If you don't know how to do them we can talk about it.

1)  3x+3

2)  6xy-9x

I am very happy to help you learn.  We just need to work out a starting point  

an exponential equation that goes through (3,64) and (5,1024)

$$\small{\text{
Exponential equation is:
$\quad \boxed{y=y_0*a^x}$
}}\\
\small{\text{
$
(1): \quad 64 = y_0*a^3 \quad | \quad (3,64)
$
}}\\
\small{\text{
$
(2): \quad 1024 = y_0*a^5 \quad | \quad (5,1024)
$
}}\\\\
\begin{array}{lrcl}
\hline
\\
\dfrac{(2)}{(1)}: &\dfrac{1024}{64} &=& \dfrac{y_0a^5}{y_0a^3} \\\\
&\dfrac{1024}{64} &=& \dfrac{a^5}{a^3} \\ \\
&16 &=&a^{5-3} \\
&16 &=&a^{2} \quad | \quad \sqrt\\
&4 &=&a\\
&a &=&4
\end{array}
\begin{array}{lrcl}
\hline
\\
(1): & 64 &=& y_0*4^3 \\
& 64 &=& y_0*64 \\
& 1 &=& y_0\\
& y_0 &=& 1\\
\end{array}
$\quad \small{\text{The exponential equation is:
}}\boxed{y=1*4^x=4^x}$$$

$$\\
\small{\text{
Proof:
}}\\
\small{\text{
$
\quad y(3) = 4^3 = 64 \quad okay!
$
}}\\
\small{\text{
$
\quad y(5) = 5^3 = 1024 \quad okay!
$
}}$$

I believe this page explains that concept pretty well:) http://www.mathsisfun.com/9recurring.html

Grade in this context is like the slope of the road, its steepness, if you will:)

The grade of 28.4% would mean an incline/decline of 28.4 feet for every 100 feet traveled on the road.

The anwser is 9075.

3x² + x²

These are "like terms" -- they have exactly the same variables, so add their coefficients:  3 + 1 = 4

Answer:  4x²

THe legnths of any two sides of a triangle, when added together, must be longer than the third side.

So:  10 + x > 12   --->   x > 2   --->   2 < x

And:  10 + 12 > x   --->   22 > x   --->   x < 22

And:  12 + x > 10   --->   x > -2   (Since, by the first inequality, x > 2; for x to be both > -2 and > 2, it must                                                               be > 2, so we'll throw away this answer.)

Since 2 < x and x < 22, we get:  2 < x < 22

6    3+3=6

The calculator at this site will be able to give you this answer very quickly.

One meter is approximately 39.37 inches.

One yard is 36 inches.

Therefore, one meter is longer than one yard, and eight meters are longer than eight yards.

Help please!!

Billion has 9 zeros
Trillion has 12 zeros
Quadrillion has 15 zeros
Quintillion has 18 zeros
Sextillion has 21 zeros
Septillion has 24 zeros
Octillion has 27 zeros
Nonillion has 30 zeros
Decillion has 33 zeros
Undecillion has 36 zeros
Duodecillion has 39 zeros
Tredecillion has 42 zeros
Quattuordecillion has 45 zeros
Quindecillion has 48 zeros
Sexdecillion has 51 zeros
Septendecillion has 54 zeros
Octodecillion has 57 zeros
Novemdecillion has 60 zeros
Vigintillion has 63 zeros
Googol has 100 zeros.
Centillion has 303 zeros (except in Britain, where it has 600 zeros)
Googolplex has a googol of zeros

(I found this on Yahoo! Answers and I thought it was very interesting!)

The factorial of 21 is 51,090,942,171,709,440,000 I think

We need to convert 10 ft to cm = 120 x 2.54 = 304.8 cm ... and 1m = 100cm

100m / 40cm = x / 304.8   cross-multiply

30480 = 40x        divide by 40

x = 762 cm  = 7.62 m =  [39.37/12 x 7.62] = about 25 ft

No prob, saseflower....I still gave you points.....!!!

I assume that we have

2300 x 5.35x-45,555,000=200    add 45,555,000 to both sides

2300 x 5.35x =  45,555,200       simplify on the left

12305x = 45,555,200                 divide both sides by 12305

x = 45,555,200 / 12305  = about 3702.17

Oh of course when I thought of remainder I was thinking in decimals, sorry! Thank you CPhill :)