Firstly, what you want to do is to turn both of the equations into the same form. In this case, we'll be using standard form. We end up with -6x+y=-4. We can then begin to use elimination to solve the problem. Now, I'm hoping you actually learned how to do elimination so that this next part will make sense.
In order to solve the problem, we need to isolate one of the variables, x or y. In order to do so, we need to make the x's or y's from both equations opposites. In this situation, we'll rid of the x's. Because one of the equations has a negative and the other has a positive, that part of making the numbers opposite is complete. However, we still need to make them the same number to make them truly opposite. So, we need to multiply the equations to make the x's equal. Luckily, for this problem, we only need to multiply one of the two equations.
We firstly multiply this one by three to make the 2 equal 6.
3(2x+5y=44)=6x+15y=132
Now that the 6's are opposites, we can now proceed with the rest of the problem
6x+15y=132 Now we will we will add the terms together.
-6x+y=-4 6x+(-6x)=0 15y+y=16y 132-4=128
Now put those back into the equation. Because there is no more x, we are left with:
16y=128 Simply divide 128 by 16 and you get 8. Hence, y=8. However, this is only the first part of the problem. We now use the y to find the x by putting the value of y back into the equation made previously. To keep it simple, let's use -6x+y=-4. Put the value of y, 8, back into the equation and solve.
-6x+8=-4 x=2
So, now that we know x, the point at which the two lines cross is at: (2, 8)
I hope I did this right and that it helps. Good luck!!! 