2ab(3ab-5)    distribute the "2ab" over the terms in the parenthess

6a^2b^2 - 10ab

4t+14=6t/5+7    multiply through by 5

20t + 70 = 6t + 35     subtract 6t and 70 from both sides

14t = -35            divide by 14 on both sides

t = -35/14 =  -5/2

25% = .25

So

.25 of 110.00  =

.25 x 110.00  =   your answer

The base is 4, the "-" isn't raised to the exponent........for "-4" to be the base, we would have to have (-4)^2

What did you ask?

It will be -4.

Ok I guess.

Using a complex algorithm, I was able to find the answers: 19

y = 4x - 6 when x = 0 this says y=-6 and that's where the graph cuts the y axis, and when y=0 this says 4x-6=0 meaning x=+1.5 and this is where the graph cuts the x axis. So mark those points on the axes and join up with  straight line extending it beyond these points.

It is 51.2

There's a calculator.

take 5 times (4t+14)

20t+70=6t+7

Most people answer questions in the middle of the night, because they're in a different time zone. If your questions dont get answered right away, check again in the morning.

16 different ways

AWW, SHUT UP!! WE KNOW YOU KNOW WHAT THAT IS, AND FOR YOUR SAKE ON ASKING DUMB QUESTIONS, I WON'T ANSWER YOUR QUESTION. If you were young, you wouldn't even know how to use this website.

i can give you the answer! in exchange for an answer for me!

g (x) = -5x^2,  so g (-1) = -5.

Not sure whether or not this is a troll post, but ":" means ratio. So you have 10:2 or 5:1. Five to one, or 5/1.

We want to evaluate g(-1) and then put this result back into "g"

So

g(-1)  = 5(-1)^2   = 5 * 1   = 5

So

g(5) =

5(5)^2  = 5*25  = 125

And that's it....

f(x)= 2x^3-7x+3; f(x)=1

We are trying to find the "x's" that make these are equal, so let's set them equal....

2x^3 - 7x + 3  = 1     subtract 1 from both sides

2x^3 - 7x + 2 = 0     this can't be factored.....using the onsite solver, we have

$${\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{3}}}{\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{2}}}}{\mathtt{\,-\,}}{\mathtt{2}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = -{\mathtt{2}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{0.292\: \!893\: \!218\: \!813\: \!452\: \!5}}\\
{\mathtt{x}} = {\mathtt{1.707\: \!106\: \!781\: \!186\: \!547\: \!5}}\\
{\mathtt{x}} = -{\mathtt{2}}\\
\end{array} \right\}$$

Note, we could have used the Rational Zeros Theorem to find the first root of -2, and then used the Quadratic Formula to find the other two solutions........

a^2-ab-ba+b^2

a^2-2ab+b^2

21 is your answer.

the answer is 4. what grade are you in kindergarden?

5 + 2*5+4*5+-4*5+-2

5+10+20-20-2

5+10-2

15-2

13//

I think X meaning is *(mutipy). so i solve this question in easily.

4+7

11//

 that is the answer. that's a simple question.