All Answers 358514 Answers

There are several ways to do this.......let's find 1/2 of a side length of the octagon

We have

(1/2)s/sin22.5 = 4.5/ sin 67.5

(1/2)s = [4.5 sin 22.5] / sin67.5 = about 1.864

So we have 8 triangles with heights of 4.5 and a side length of about 3.728

So, the area is given by

8 * (1/2) *3.728 * 4.5  = about 67.1 sq units

To get the discount we use   [Old Price - New Price[ / Old Price....so we have

[19.50 - 8 ] / 19.50 = about .59  =  about 59%

$${\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{524\,952}} = {\mathtt{1\,649\,185.346\: \!687\: \!269\: \!140\: \!117\: \!4}}$$ 

6(2m - 1) = 138   simplify

12m - 6 = 138    add 6 to both sides

12m = 144    divide by 12 on both sides

m = 12

asin     acos     And  atan

10.. his dad has 2 he had twelve 12-2=10 

maybe use a protractor or if the question is one where you have to find the amount of x on a straight line with f a straight line is 180 so you take the angle that you are given and then minus that from 180 that gives you the angle of x

for example:

to find x you would minus 92 from 180 to find angle x

                      /

                    /

          x      /    92

  __________________________

It will take 400 hours to get 600 dollars with 1.50 an hour.

i really dont know

21

The boy has 2 euros. 12 - 2 = 10

oh sorry melody ill do it again!

my answer is funny!

$${\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{50}}{\mathtt{\,\times\,}}{\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{60}}{\mathtt{\,-\,}}{\mathtt{60}}{\mathtt{\,\times\,}}{\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}$$

$${\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{50}}{\mathtt{\,-\,}}{\mathtt{60}}{\mathtt{\,-\,}}{\mathtt{60}}{\mathtt{\,\times\,}}{\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}$$

$${\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{50}}{\mathtt{\,-\,}}{\mathtt{60}}{\mathtt{\,-\,}}{\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}$$

$${\mathtt{50}}{\mathtt{\,-\,}}{\mathtt{60}}{\mathtt{\,-\,}}{\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}$$

$${\mathtt{\,-\,}}{\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}$$

$${\mathtt{\,-\,}}{\mathtt{10}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}$$

$${\mathtt{0}}$$

The abstract science of number, quantity, and space

$${\mathtt{1}}{\mathtt{\,\times\,}}{\mathtt{106}} = {\mathtt{106}}$$

$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{53}} = {\mathtt{106}}$$

$${\mathtt{53}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{106}}$$

$${\mathtt{106}}{\mathtt{\,\times\,}}{\mathtt{1}} = {\mathtt{106}}$$

Hi Rosala,

you have it the wrong way around.

106 is divisable by 2

or, you could say 2 is a factor of 106

or 106 is a multiple of 2

106 is divisible by 2 , 106  is divisible by 1, 106 is divisible by 106......

0 + 50 x 1 - 60 - 0 + 10 =

= 50 - 60 + 10 =

= -10 + 10 =

0