11 − 2(2x − 5) = 5(2x + 1) − 4(3x − 1)
11-4x+10=10x+5-12x+4
21-4x=-2x+9
12=2x
x=6
4 and 15
You can use the Pythagorean Theorem twice.
The diagonal across the bottom has the sides of a right triangle 12 and 15. Diagonal= 19.2 (don't round result just yet).
Then use this diagonal and the given height (30) in another triangle.
The diagonal of the new triangle is 35.6 to the nearest tenth.
Anonymous is correct, but just a useful tip:
When you want to make a decimal a percent, move the decimal point over 2 spots to the right
Another way of solving that is to make a proportion
37/100 = x/600
Cross multiply
100x = 22200
Divide by 100 on both sides
x = 222
Product is the result from multiplication.
$${\mathtt{0.37}}{\mathtt{\,\times\,}}{\mathtt{600}} = {\mathtt{222}}$$
$${\mathtt{0.006\: \!4}}{\mathtt{\,\times\,}}{\mathtt{2\,000}} = {\frac{{\mathtt{64}}}{{\mathtt{5}}}} = {\mathtt{12.8}}$$
It does not ask you for the shortest route, it asks for the number of distinct routes!
$${\mathtt{5\,100\,000\,000}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5\,600\,000\,000}} = {\mathtt{10\,700\,000\,000}}$$
$$\frac{30rt}{6t}$$
$$\frac{5r(6t)}{6t}$$
5r
You must travel on the line, not on the square. Why else would you start at point A, which is the lower left? It does not say to start at the lower left block.
The instructions definitely say to draw a 6x6 square. So there are no "3 up and 3 across" routes.
Christmas Goose indeed!
I'll bite!
To traverse the square don't you follow the line around the edge if it is a path? Considering this, does't each square require two choices?
@Nigerian Prince..........why did you stop sending me emails????.........I always enjoyed those so much........!!!!
To convert this to an improper fraction......mutiply the 4 time 8 = 32 ....add the 3 to this = 35. Then, put this result over the 8......so....
8 + 3/4 = 35/8
hes a cool man...so.....cool man...cool salute.....got it?
its called ...logic!
Because you are a bug. Bugs have a life, but they don’t usually use math. Bees do and they have a good life.
pitoooooooooo
All 6-unit paths from A to B are 3 up and 3 across. Just choose 3 of the 6 (This pertains to 6-unit paths only. Not 12 unit paths, or 9-unit paths, or the path of a Christmas goose).
$$\; Solution: \\\\ \left( {\begin{array}{*{20}c} n \\ k \\ \end{array}} \right) = \dfrac{{n!}}{{k!\left( {n - k} \right)!}}\; \hspace{15pt}| \hspace{15pt} \Text {n=6 \; k=3} \\ \left( {\begin{array}{*{20}c} 6 \\ 3 \\ \end{array}} \right) \; = \; 20 \; \tezt {paths}\\$$
99.5%
$$Iam$$
That is not a statement. It is a question.
i am i Nigerian prince and you've just won £100,000,000
