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1.

$${\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{9}}$$

$${\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{9}}$$

$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{15}}$$

Yes Mellie, you made a typo.

3^2=9

Yes it does have a lot of great features :)

Insert them where ?  

No rude comments thank you very much  

This is a serious response!

I used simultaneous equations. x=number of days in Tampa, y=number of days in orlando

$${\mathtt{275}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{400}}{\mathtt{\,\times\,}}{\mathtt{y}} = {\mathtt{2\,300}}$$ (1)

$${\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{y}} = {\mathtt{7}}$$ (2)

$${\mathtt{275}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{275}}{\mathtt{\,\times\,}}{\mathtt{y}} = {\mathtt{1\,925}}$$ (3)

Take (3) from (1)

$${\mathtt{125}}{\mathtt{\,\times\,}}{\mathtt{y}} = {\mathtt{375}}$$

Therefore y = 3 (375/125)

Now sub [y=3] into (2)

$${\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{7}}$$

Therefore x = 4

Now we know that you should spend 4 days in Tampa and 3 days in Orlando.

(we can also solve this by guessing that x=4, y=3 and then checking with an equation)

I just googled "Nike Stefan Janoski shoes greys ans crystal mint" I think

I went straight to pictures of course :)

That has no solutions   the number must be between   -1 and  1  

$$2\sqrt{75}\times\sqrt{72}$$

$$2\sqrt{75\times72}$$

$$2\sqrt{5400}$$

$$2\sqrt{100}\times\sqrt{54}$$

$$2\times{10}\times\sqrt{9}\times\sqrt{6}$$

$$2\times{10}\times{3}\times\sqrt{6}$$

$$60\sqrt6$$

Area of a square = length^2

$$x^2=361$$

$$\sqrt{x^2}=\sqrt{361$$

$$x=19 ft$$ 

1 - 1/3 = 2/3

you probably mean

3x^2 – 4, for x = –3

3*(-3)^2-4 = 3*9-4=36-4=32

The answer is 4 and 16/24.

That is an approximation zegroes

$${\mathtt{\pi}} = {\mathtt{3.141\: \!592\: \!653\: \!589\: \!793\: \!2}}$$

and that is still an approximation.

1, because there's no number that goes into 1 other than itself. So the answer is 1.

$${\sqrt{{\mathtt{21}}}} = {\mathtt{4.582\: \!575\: \!694\: \!955\: \!84}}$$

This is approximate

It depends on what n equals, you need to work out what that means first.

132 =  

66 x 2  =

11 x 6 x 2 =

11 x 3 x 2 x 2 =

11 x 3 x 2^2

(4n + 5)(n + 1)

NASA hasn't created a rocket that travels that fast yet, so although that's kinda true it's impossible. So, the only way is by travelling at 6968 miles per second.

There are 9 b***s in a sac. There are 3 reds b***s, 2 white b***s and 4 black b***s. If three b***s are drawn from the sac without replacement.

i. find the probability that the 1st ball is red and the last ball is black

I wasn't really sure but I did it 2 ways and got the same answer so I feel confident reasonably. 

I knew the second way was fine but this is the easier way.

It would be the same as if the first ball was red and the second one was black and the last anything.

(3/9)*(4/8)*(7/7)=1/6

ii. find the probabilty that the 1st ball is black and the last ball is either white or black

(4/9)*(6/8)*(7/7) = 1/3

The distance across the Milky Way is about 100,000 light years.....thus......

You would need to travel at 100,000/60 = about 1667 light years per second to cross the Milky Way in one minute

And since a light year = about 5.9 x 10^12 miles.....then

1667 x 5.9 x 10^12  = 9,835,300,000,000,000   about 9.8 quadrillion miles per second  (US measure)

Use a calculator and do the second fucntion of tan and then insert the number between the brackets 

CPhill is, he posted this on the forum a couple of hours ago, that is how I know   

take both sides to the power of (1/5)

Honestly I don't know sorry