All Answers 358093 Answers

$${\mathtt{y}} = {\frac{\left({{\mathtt{e}}}^{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{\left({{\mathtt{e}}}^{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}\right)}}\right)}{\left({{\mathtt{e}}}^{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{\left({{\mathtt{e}}}^{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}\right)}}\right)}}$$

$${\mathtt{y}} = {\frac{\left({\frac{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{{{\mathtt{e}}}^{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}}}\right)}{\left({\frac{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{{\mathtt{e}}}^{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}}}\right)}}$$

$${\mathtt{y}} = {\frac{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right)}}$$

$${\mathtt{y}} = {\frac{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right)}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right)}}$$

$${\mathtt{y}} = {\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right)}}$$

$${\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{1}} = {\frac{{\mathtt{2}}}{\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right)}}$$

$$\left(\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{1}}\right){\mathtt{\,\times\,}}\left({{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right)\right) = {\mathtt{2}}$$

$${{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,-\,}}{\mathtt{1}} = {\frac{{\mathtt{2}}}{\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}}$$

$${{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)} = {\frac{{\mathtt{2}}}{\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}$$

$${{\mathtt{e}}}^{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)} = {\frac{\left({\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}}$$

$${\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}} = {ln}{\left({\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{\mathtt{\,\times\,}}{ln}{\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}$$

$${\mathtt{x}} = {\frac{\left({ln}{\left({\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{\mathtt{\,\times\,}}{ln}{\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}\right)}{{\mathtt{12}}}}$$

5/6+1/4 =     getting a common denominator, we have

20/24 +  6/24   =  26/24   =   13/12

10^-2/10^-4  =  10^-2-(-4)  =  10^2

You will need to multiply the number of crates times the number of cans in each crate:  

125 x 48  =          <--- the answer  

$${\mathtt{20.25}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {\mathtt{169}}$$

$${{\mathtt{b}}}^{{\mathtt{2}}} = {\mathtt{169}}{\mathtt{\,-\,}}{\mathtt{20.25}}$$      

  b =$${\sqrt{{\mathtt{169}}{\mathtt{\,-\,}}{\mathtt{20.25}}}} = {\mathtt{12.196\: \!310\: \!917\: \!650\: \!468}}$$

Gruß radix !

This is a broad topic that obviously can't be covered in a concise answer.  This may get you started:

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83-[59-(22-18)]

22-18=4

59-4=55

83-55=28

$${\mathtt{83}}{\mathtt{\,-\,}}\left[{\mathtt{59}}{\mathtt{\,-\,}}\left({\mathtt{22}}{\mathtt{\,-\,}}{\mathtt{18}}\right)\right] = {\mathtt{28}}$$

@Dukemort

This just illustrates the fact that computers generally don't store floating point numbers exactly.  The result of the first division is only approximately 3.14159...etc.  (Here it is, correct to 40 significant figures: 3.141597013388439272057065364416526894688, but even this is an approximation). Hence when this value is multiplied by the original divisor, it doesn't reproduce 360 exactly, though it's pretty close!

@ TitaniumRome

The commutative property is when a*b = b*a  for multiplication; or a + b = b + a for addition.

.

You probably mean the following;

$$\frac{2^5}{8}\rightarrow\frac{2^5}{2^3}\rightarrow2^{5-3}\rightarrow2^2$$

.

1/18 y = -1/11

multiply both sides by 18 then

y= -18/11  =  - 1  7/11

Ahh, multiplication 

$${\mathtt{180}}{\mathtt{\,\times\,}}{\mathtt{160}} = {\mathtt{28\,800}}$$

Seems to me like the real question is:

what property does this expression/equation belong to best?

i think this is communitive property

Dont get the joke

$${{\mathtt{e}}}^{-{\mathtt{286.073}}} = {\frac{{\mathtt{1}}}{{{\mathtt{e}}}^{{\mathtt{286.073}}}}}$$    =    $${\mathtt{5.755\: \!39}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{125}}}$$

Sorry, that should be   (1-1-3-5-7)/3  -  9/3  =   -24/3 = -8

(1 +  -1  +  -3  +  -5  +  -7 )/3      +   9/3  =  ( -15 + 9 )/3   = -6/3  =  -2

Sorry; my friend. I don't understandt it well...

.30 (.3-.36)/SQRT(.36(1-.36)/200)  =  -.018/SQRT(.36(.64)/200) = -.018/SQRT(.001152)  =  -.53033008588991034903877

Not all calculators have 'Fraction Buttons'      You may have to just divide the fraction out, i.e. 4/3  is 4 divided by 3.     SOME calculators MAY have a button that show x/y as the fraction button.   SOME calculators are as answered in answer #1

You probably can't.   Solve the equation using the = sign and when finished substitute the < symbol for the =.

$${\frac{{\mathtt{4}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{6}}}^{{\mathtt{3}}} = {\mathtt{904.778\: \!684\: \!233\: \!860\: \!452\: \!7}}$$

the fraction button  is  left  of  the great  C   (web2.0calc )     You see this:   /

No, Alan...I worked it out, too....there's no "whole" number answer possible based on the available info........

Let x =  initial number red      ....the (3/2)x = initial number blue  ....  y=  initial  number green 

Before the sale, we have:

x + (3/2)x   + y = 1686         →              (5/2)x + y = 1686     (1)

After the sale, we have:

(1/2)x + (1/4)(3/2)x + y = 922       →     (7/8)x + y =    922      (2)

Subtract (2) from (1)

(13/8)x = 764       x =  about 470   initial red

(3/2)x =  about 705  initial blue

Rats!!!.....heureka beat me to it  !!!!!