Bredth =B

length = 3B

perimeter = 3B+B+3B+B = 8B  units

Area = $$3B*B = 3B^2$$     units^2

Perhaps you mean:

$$\\\frac{(6-2ab-18^2b^3)}{12}\times a^4b\\\\
=\frac{(3-ab-9^2b^3)}{6}\times a^4b\\\\
=\frac{a^4b(3-ab-81b^3)}{6}\\\\$$

Now, if you want to, you could expand the brackets.

You are very welcome :)

Thank You 

Good work RT       (aka TR)

The formula for a circle is $$(x-h)^2+(y-k)^2=r^2$$

Where (h,k) is the centre of the circle and r is the radius    

Sorry that was a mistake 

who or what is Brosef ???

There are no equations!     

There are some really good stats calculators that are referenced in the "Reference Material"  Sticky topic :)

Maybe this is what you mean ?

$$\\\frac{100}{3}\times 10^{-11}\\\\
33.\bar{3}\times 10^{-11}\\\\
3.3\bar{3}\times 10\times 10^{-11}\\\\
3.3\bar{3}\times 10^{-10}\\\\
\frac{3.3}{10^{10 }}$$

Sorry I did not see your post there before.  

Happy birthday Rose98,

looks like the evil orginization is behind this

prepare....for anything

*grabs desert eagle, begins problem

so 25-12=13

addition-related, hmm, you prehaps looking for this equation:

$${\mathtt{13}}{\mathtt{\,\small\textbf+\,}}{\mathtt{12}} = {\mathtt{25}}$$?

that perhaps is what youre looking for

he better have a weapon to protect him

34 minutes on the streets can be the last 34 minutes of your life

you never know when youll encounter a phsyco, which is why i always carry a desert eagle

hey, watch your mouth, Main Ego!

and the names Royal, not alt. ego

hehe, maybe a cia agent is too good for a stupid villain

*shoots you directly in the eye (my id code grants me the rights to k**l anyone)

on this calc use arc tan   

It is the same as inverse tan

atan(5.5/9.3)=

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{5.5}}}{{\mathtt{9.3}}}}\right)} = {\mathtt{30.599\: \!978\: \!693\: \!209^{\circ}}}$$

alt. ego, you shouldve saved that question for me at least!

now im as mad as ever, how dare you CIA Agent mess with me, the greatest villain the school has ever seen!

my alternative ego, what do you want? trying to take the spotlight away from me? you see, im too busy taking over the world that i simply dont have time for you to **** around my place, you can go off and do your dumb cia stuff, being a villain is way better than being a cia agent

Thanks Chris, Sabi and Dragonlance,

I'll just put my 2 bob's worth in :)

$$\\\frac{x^2-4+4}{x-3}>0\\\\
\frac{(x-2)^2}{x-3}>0\\\\
x\ne 3\\\\
\frac{(x-2)^2}{x-3}\times (x-3)^2>0\times (x-3)^2\\\\
(x-2)^2(x-3)>0\\\\
consider\;\; y=(x-2)^2(x-3)\;\;\\\\$$

You are right Sabi this is not a parabola but it is a polynomial - (a parabola is a polynomial of degree 2) 

When will the graph be above the x axis?

There is a root at x=3, and a double root at x=2.

The highest power of x is 3 That is the degree of this polynomial is 3.

This means that the graph will have 3 directions.

I can immediately see that the coefficient is X^3 is 1. i.e.   The leading coefficient=1.

A positive leading coefficient means that the graph will finish in the top right hand corner.

So I know a lot about how this graph will look, just by a cursory examination of the formula.

I know that it will look like this!

I can see from the graph that this is greater than 0 when x>3

---------------------

I wrote this post some time ago, I just fished it out of our reference material sticky topics.

It would be a very good idea for you to try and make sense of it all.

I have done the top row of graphs, maybe you would like to take a look at the bottom row :))

He averages  one mile evey 17 minutes.....thus....it would take him 34 minutes to walk two miles

>51 minutes

Remember, Dragonlance, x = 3 isn't a  part of the solution.......I'm just doing this to find the interval points.......the solution is x > 3 as sabi92 found ....  or....as I gave ..... (3, ∞ )......both of these are the same solutions

You can arrange them into a 1 x 15 rectangle or a 3 x 5 rectangle, so there are 2 unique answers.