My turn to try:
f(x)=x^2+9x+18
y=0^2+9*0+18
y=0+0+18
y=18
You confused me with a new question. LOL
YES If f(x)= x^2 +9x+18 then the y [really f(x) ] intercept is 18
SO (0,18) would be one point on the graph. :))
y=x^2+9x+18 is a polynomial function
This is because the y is out the front by itself and There are a list of terms with x^(some integer) aded or subtracted together after the equal sign.
That is a VERY lay explanation but it will do for the moment. :))
The number that is tacked on the end, the constant, will always be the y intercept!
Now the highest power of x gives the number of directions that the graph will take (sort of anyway). This is called the degree of the polynomial.
Lets look at thes polynomial functions.
y=3x+7
y=3x^1 +7
the y intercept is 7
the highest power(degree) is 1 so it only has one direction. Bingo...It has to be a line!
y=7x^2+12x+5
The y intercept is 5
the degree is 2 so it has 2 directions. Bingo... It has to be a parabola
y=-6x^3-5x^2+12x
The y intercept is 0 (there is no constant...well there is it is an invisable 0)
The degree is 3 so it has 3 directions so it is (probably) like a sideways S
I say probably because occassionally the directions are not clear and they look more like little kinks in the graph. But don't worry about that.
Yours is y=x^2+5x+6
Tell me about its basic shape please. :))