An equation of this type: ax +by = c, where a, b, c can have numerical values.
-4x+y-5x-y=27
-9x=27 |:(-9)
x=-3
1.7724538509055159
Hallo guest!
how do I make it so that when I put in sqrt3(5)*sqrt(5)/(sqrt3(5^5) I see is as the answer in sqrt form
If you mean: [sqrt(3) X 5 X sqrt(5)] / [sqrt(3) X 5^5], then:
=1/(125 sqrt(5))=1 / (5^3 sqrt(5))
assuming sqrt3 means cube root,
sqrt3(5)*sqrt(5)/(sqrt3(5^5). The easiest way to solve this is to write the sqrt and sqrt3 as exponents:
= (5^(1/3)) * (5^(1/2) ) / ((5^5)^(1/3))
= 1/sqrt(sqrt3(5^5))
Another way
([5 * 6 ] - 4 ) * 10 =
( 30 - 4 ) * 10 =
26 * 10 =
260
By sqrt3
Do you mean cubed root?
5/8/8
Or
(5/8)/8
2×{6+[12÷(3+1)]}-1 =
2*{6 +[ 12 / 4] } - 1 =
2* { 6 + 3} - 1 =
2* {9} - 1 =
18 - 1 =
17
Just enter it like this:5/8/8 and then hit the = sign. That should do it.
Simplify the following: 2 (12/(3+1)+6)-1 3+1 = 4: 2 (6+12/4)-1 The gcd of 12 and 4 is 4, so 12/4 = (4×3)/(4×1) = 4/4×3 = 3: 2 (6+3)-1 6+3 = 9: 2×9-1 2×9 = 18: 18-1 | 1 | 8 - | | 1 | 1 | 7: Answer: | =17
You needed to divide :)
[(4 X 5) + 6] X 10=260
It's actually an "old" avatar that I'm recycling........thanks, anyway.....LOL!!!!!
9 times
Just divide 36/4=9 pages needed
you are right thanks
This has an infinite number of solutios. It is the equation of a hyperbola.
Always give an example, so we can show you how to do it, if it can be done.
x+y=-2
There are infinite solutions to your problem such as:
x=-3, y=1
x=4, y=-6
x=-2, y=0..........etc.
it's 4
Maybe one of the equal signs on the second line is meant to be a + or a - ?
