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We would have to know at least one side and the measure of the angle opposite that side......all 30-60-90 triangles are similar......so there are infinite side length combinations possible......

Last​ year, a​ college's tuition 42,500. This​ year, the tuition increased by​ 4%. Find this​ year's tuition by using a percent greater than 100.

Last year's tuition=$42,500

This year's tuition=$42,500 X 104%=$44,200

At the of 99 years, $5,000 will be worth=$257,178.12. You have to use this formula for this:

FV=PV[1 + R]^N=FV OF $1 TODAY, Where R=Interest rate per period, N=number of periods,  PV=Present value, FV=Future value.

Solve for s:
s^2 = 32500+30000 sin((2 pi)/9)

Take the square root of both sides:
Answer: | s=+or- 227.560........
 

(2/5) ( n + 3 )  = 4    multiply both sides by 5/2

n + 3 = 4(5/2)

n + 3  = 10   subtract 3 from both sides

n = 7

88 + 16x + 8  =

88 + 8 + 16x =

96 + 16x

80% of the original price

9/5÷4÷(-3)

9/5÷4  =

9/5 * (1/4)   =

9/20

And

9/20 ÷ -3  =

9/20 * (-1/3) =

-9 / 60  =

-3 / 20

Solve for n:
(2 (n+3))/5 = 4

Multiply both sides of (2 (n+3))/5 = 4 by 5/2:
((5×2 (n+3))/(2))/(5) = 5/2×4

5/2×4 = (5×4)/2:
(5×2 (n+3))/(2×5) = (5×4)/2

(5×2 (n+3))/(2×5) = (2×5)/(2×5)×(n+3) = n+3:
n+3 = (5×4)/2

4/2 = (2×2)/2 = 2:
n+3 = 5×2

5×2  =  10:
Answer: | n=7   

The diagonals of a rhombus are perpendicular and bisect each other.......thus....by the Pythagorean Theorem...

Side length  =  sqrt[6^2 + 4^2]  = sqrt [ 36 + 16 ]  = sqrt [ 52]   = 2sqrt [13]

That reminds me of the one in my school gym.

"Seven days without exercise makes one weak."

The answer is 7.

-3 + 6 = 3

how about

-3 + 6 = 

-9 - 3   = - (9 + 3)  = - 12

1PM - 2:40PM   =  100 minutes

So.....each task takes 50 minutes

And the third task lasts 50 minutes, too.....so

2:40PM + 50 minutes   = 3:30 PM is when the last task is completed....

7 doesn't have a full number root. it would be a decimal number a long one 2.6457513110645906 or you could round it to 2.65

wait what's the question I don't understand

I'm not sure maybe you should put the first number in () like this (-6) or something like that

Just enter your number and press +- key just to the right of zero. That should make it negative.

Very nice, Dragonlance.....a BIG 5 points from me.....!!!!!

Simplify the following:
(2 p^2+30 p+108)/(p^2+5 p-6)

The factors of -6 that sum to 5 are 6 and -1. So, p^2+5 p-6 = (p+6) (p-1):
(2 p^2+30 p+108)/(p-1) (p+6)

Factor 2 out of 2 p^2+30 p+108:
2 (p^2+15 p+54)/((p+6) (p-1))

The factors of 54 that sum to 15 are 9 and 6. So, p^2+15 p+54 = (p+9) (p+6):
(2 (p+6) (p+9))/((p+6) (p-1))

(2 (p+9) (p+6))/((p+6) (p-1)) = (p+6)/(p+6)×(2 (p+9))/(p-1) = (2 (p+9))/(p-1):
Answer: | (2 (p+9))/(p-1)

Total area / area  of each paver  = the number we need......so

[ 2p^2 + 30p + 108 ]  / [ p^2 + 5p - 6]    factor top/bottom

[2(p ^2 + 15p + 54)] / [ (p +6)(p-1) ] =

[2 (p + 9) (p + 6)] / [ ( p +6) (p -1) ]  =

[2 (p + 9)] / [p - 1]  =

[ 2p + 18] / [ p - 1]   = the number we need

The broken part will form the hypotenuse of a right triangle...call this x

And we know an angle and an adjacent side [19] to this angle.....

So.....the trig relationship  that best describes this is the cosine.....so

cos 75  = 19 / x     rearrange

x  = 19 / cos 75  = about 73.41 ft

And the height of the standing part, h, can be found by the tangent.....so we have

tan 75 = h / 19

h = 19 * tan 75 = about 70.91 ft

The total height of the pole is the sum of these =  73.41 + 70.91  = about 144.32 ft

What is 4n-6= 10n

4n-6= 10n isolate n to one side

-6=10n - 4n

-6=6n divide both sides by n

n=-1