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Well....at midnight, the second hose has been operating for 8 hours.......so....it must have put

8hrs x 60 min x 8 gal/min  =  3840 gal of water into the tank

So......the first hose  must have put  7740 - 3840 = 3900 gal of water into the tank.....so the number of hours it operated can be found as :

Hrs  operated x 60min x  5 gal/min = 3900 gal

Hrs  operated  x 300 gal  = 3900 gal

Hrs operated  = 13    [after 9AM]

So....it was turned off at 10 PM

You are very welcome! Ask your questions,if you are confused. We can help again!

(CPhill might get angry!)

Well, thanks for the +5 points!

Yes, sorry for the typo...copy and paste messed it up. Thank you both, I understand it perfectly now :)

3x^2+14x+8   =

(3x + 2) (x + 4)

I assume that the first one is :

lim x → −∞ 4e^x = 0

Note that, as x  → −∞, e^x will grow smaller and smaller.....and if we let x assume some large negative value, e^x, will approach 0

Therefore,

lim x → −∞ 4e^x = 0

Likewise, I assume that the second one is :

lim x → ∞ 2e^x = ∞

Again, if we let x approach some large positive value, e^x will grow larger and larger. So, as x → ∞ , e^x  will also approach ∞

Here's the graph of e^x that will give you some idea of the end behaviors of both functions :

https://www.desmos.com/calculator/ml0aj0en2z

If you use dimensional analysis, it looks like this (note that the sec  and the  min and the hr units will cancel out laeving only  mi/day)

 123456789   mi     x   60    sec    x   60  min  x  24   hr         =     1.066666 x 10^13   mi

                      sec                min               hr             day                                            day

I will try to help.

Lim x → −∞ 4e^x=0 
because you can change it to look like 
Lim x → ∞ 4/e^x 
Then the denominator gets big so it goes to zero

But listen to the BIG BOSS first. I am trying to help, so I may be incorrect. CPhill, the class genius, will tell you the answer, and maybe correct me.

This can be easily done on the forum's calculator, but oh well.

5% of 540 = 27

27 is your answer.

An equation says that two things are equal. It will have an equals sign "=" like this:

7 + 2 = 10 − 1

That equation says: what is on the left (7 + 2) is equal to what is on the right (10 − 1)

So an equation is like a statement "this equals that"

Here is another equation:

aaa midnight :)

10 x 4 = 40

\(10*4=\boxed{40}\)

Hope it helped!

Laugh, my old friends. Thee time to slay thee evil dragons has 'ought to come.

\(\frac{9}{8}(-9)=-10.125\)

-10.125 is your answer! Hope it helped.

Decimal to Fraction

1) As an example, convert 0.625 to a fraction.

2) Multiply 0.625/1 by 1000/1000 to get 625/1000.

3) Reducing we get 5/8.

Hope it helped!

At 9:00 am, an empty water tank begins to be filled with water flowing through a hose at a rate of five gallons per minute. Seven hours later, water flowing through a second hose also starts to fill the tank at a rate of eight gallons per minute. Some time later, the first hose is turned off but the second hose continues to be used to fill the tank. At midnight the 7740-gallon tank is finally full. At what time was the first hose turned off?

The second hose was turned on from 4:00pm till midnight or for 8 hours.

8 hours X 60=480 minutes that the 2nd hose was turned on.

480 X 8 gallons/minute=3,840 gallons of water from 2nd hose.

We know that 1st. hose was on for at least 7 hours.

7 hours X 60 X 5=2,100 gallons of water from 1st. hose

3,840 + 2,100=5,940 gallons from both hoses

7740 - 5940 =1,800 gallons to come from 1st hose.

1800/(60 X 5)=6 hours that the 1st. hose was running after 4:00pm

Therefore the hose was running till: 4 + 6=10:00pm. which is the time it was shut off.

i think it cannot be determined from the information given above  there is can be many answers

many thanks to you both.

That still gives me a decimal.

Not sure of what you want.  √3 (5+√3) 

You can write it like this:5sqrt(3)+3.

That is because this calculator cannot handle very large or very small numbers. That is why it sometimes says "infinity". At any rate, here is the answer to your question of .11^300=2.6170..... X 10^-288.

Just hit the "2nd"  button.......you will see "atan"   [tangent inverse ]

Here you go :   http://www.wolframalpha.com/input/?i=.11^300

this is comical, thou gaveth me a chuckle