All Answers

Me (90's Cowboys Fan, and no I don't root for Dallas): Hey guest, maybe it's a better idea to leave Hayley alone than to ruin the show, what are you doing here, get out!

Guest (90's Bills Fan, the one team that lost 4 straight Super Bowls): I was about to get her number

Me: Oh, you were, okay, good job Scott Norwood (kicker that missed wide right a field goal to give Giants the SB victory), now get out! You're ruining the show!

TitaniumRomeFeb 3, 2016

#2

+8581

0

No Comment..

Hayley1Feb 3, 2016

#1

0

What's wrong?

GuestFeb 3, 2016

#4

+8581

0

It would be the First one, then.

Hayley1Feb 3, 2016

#3

0

so would it be...

**all real numbers greater than or equal to 1

**all real numbers greater than or equal to 0

**all real numbers greater than 0

**all real numbers

GuestFeb 3, 2016

#2

+8581

0

I think that's right? If not, I'm sorry!!

Hayley1Feb 3, 2016

#6

+8581

0

Waste of time..

I personally think.

Hayley1Feb 3, 2016

#1

+8581

+5

f(x) is x +1 >= 0 {nl} {nl} x + 1 >= 0 {nl} x >= -1 {nl} {nl} for g(x), you cannot divide a number by zero. So, you set the denominator equal to zero and solve: {nl} x - 1 = 0 {nl} x != 1 (x is not equal to 1)

Hayley1Feb 3, 2016

#3

0

if the _ is under the > then you have 6 is greater than or equal to 9x...... Is that what you are asking? Divide both sides by 9 then 6/9 >= x or 2/3 or .66667 >= x

GuestFeb 3, 2016

#5

0

Yes, its childish how people act on here. /:

GuestFeb 3, 2016

#3

+8581

0

I got confused, too, Guest. :)

Hayley1Feb 3, 2016

#2

0