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just hit the / button on your keyboard

:)

logarithm of number 9 to base 3

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We're just asking ourselves, what exponent (power) do we put on 3 to raise it to 9??

In other words

log₃9

In exponential form, we have

3^x = 9

Do you see what the answer is ????  (I hope) 

Life would be great.

d**k

Well, if the total length is (174+336)ft = 510ft you need to divide this by 6ft to find how many sections.  You can calculate what 510/6 is (use the calculator on this site if necessary).

Do you just want to simplify this?

(2x-5)² - (1-x)(1+x)  = 4x² - 20x +25 -(1+x-x-x²)  =  4x² - 20x +25 - 1 +x²  = 5x²-20x +24

Awnsere please

The prime factors are 2, 3 and 7.  Non-prime factors are 6, 14 and 21.

CAN SOME ONE TELL ME

CAN SOME ONE TELL ME

(2^(x+4)/49)

seriously dude its 4

i dont think you have a d**k

5 3/4 X 2 3/5=

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OK...let's convert both things to fractions

5 3/4 = 23/4          2 3/5 = 13/5

Now, we have

(23/4) * (13/5)

If we can "reduce," we should, but unfortunately, nothing "cancels."

So we have (23 * 13) / (4 * 5) = 299/20

Writing this back as a "mixed number," we have

14 + 19/20    

its easy.... you take a gun, and you aim it at your head, and then say goodbye to life  because pepole like shouldnt live! or atleast not to be on this website 

how do I figure logrhthms on calculator other than power 0f 10

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Let me show you how to do this ...... 

Suppose we have log_a(b)   where "a" is the base and "b" is what we're trying to take  the log of.... (that's some bad English, isn't it??)

Exponentially, what this says is

a^x = b

Now take the "log" of both sides .....  we have

loga^x = logb

And, by a property of logs, we can bring the "x" out front

(x)loga  = logb

Solving for x gives

x = log(b)/log(a)

And "x" is just the exponent (power) that we need to "raise" "a" to in order to obtain "b"

But, that is the definition of a logarithm.

So, to find the log in any other base than 10 or "e," just divide the log of the number you're trying to find the log of by the log of the base you're using......  

TY 

it works!

a car consumed in its first ride 25% of her fuel. on the second ride she consumed 20% fuel of the remaining fuel in the car ( after using 25%) after the 2 rides the remaining fuel amount of was bigger by 8 than the amount of fuel used for both rides together.

what L of fuel the car had at the begining ? (before the rides)

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OK........let's call the amount of fuel in the tank before the rides = x

After the first trip, we used .25x, so we have [x - .25x] = .75x left

On the second trip, we used 20% of what remains = .20[.75x]

So, what we had left after the first trip less what we consumed after the second trip is "8 more" than what we used on both trips. Mathematically, this sets up as:

[.75x] - .20[.75x] - 8  = [.25x] + .20[.75x]

Notice that, if the left side is "8 more" than the right, then we have to subtract 8 to "equalize" both sides.

So we have

[.75x] - [.15x] - 8 = [.25x] + .20[.75x]

Simplifying, we have

[.60x] - 8 = [.25x] + [.15x]

[.60x] - 8 = [.40x]

Subtract [.40x] from both sides

[.20x] - 8 = 0

Add 8 to both sides

[.20x] = 8

Divide by .20 on both sides

x = 40L

Make sure that you check this answer in the original equation......I think it "works"  

37,000($)*0.02 = 740

or

$${\frac{{\mathtt{37\,000}}{\mathtt{\,\times\,}}{\mathtt{2}}}{{\mathtt{100}}}}$$  = $${\mathtt{740}}$$

70,800---------------> 1

? <------------------ 0.04

0.04*70,800/1=2832

225/4 simplified

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Factoring 225, we have 5² * 3²

Factoring 4, we have 2²

So 225/4 =  [ 5² * 3² ] / [2² ]

Thus, this IS simplified........(nothing on "top"  and "bottom"  "cancels")

All we can do to "simpify" this is to express it as a mixed number..........56 + (1/4)  

domain and range of {(-2,4), (3,9), (-3,4), (5,1)}

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In a simplistic manner, "domain" asks, "What "x" values are included in the set?"

These would be {-2, 3, -3, 5}

Likewise, "range" asks, "What "y" values are included in the set?"

These would be {4, 9, 1}

Thanks, Bertue.........you must have heard the old story about Gauss using EXACTLY that method to find the sum of the 1st 100 digits as an classroom assignment when he was 10 years old.

I much prefer your method to mine!!!

your momdgjetujet

a positive times a negative is always a negative. -32 my friend.