All Answers 358524 Answers

Shhh im secretly batman.

Nice poem/quote

What do you mean?

Expand the following: (4 x-1) (x+2) = (4 x) (x) + (4 x) (2) + (-1) (x) + (-1) (2): 4 x x+2 4 x-x-2 4 x x = 4 x^2: 4 x^2+2 4 x-x-2 2×4 = 8: 4 x^2+8 x-x-2 8 x-x = 7 x: Answer: | | 4x^2 + 7x - 2

Sorry Bruce you need to follow order of operation rules

Brackets first   then

Indices (powers) next   then

Division and Multiplication   {left to right)   then

Additions and Subtraction (left to right)

BIDMAS

3+3x3-3+3

=3+  9  -3+3

=12-3+3

=12

3+3=6

6x3=18

18-3=15

15+3=18

so (18)

rarinstraw1195:

What is the AREA of a rectangle?

2((4x-1)+(x+2))

2(4x-1)+2(x+2)

8x-2+2x+4

Your expression will be 10x+2

Hayley!!! I said no last time!!! :P

Bye

Tom replaced his poision with a weaker poision but bob replaced his with and even weaker one?

  -5x-7=8y      →  -5x - 8y = 7        (1)

   3y=-2x-9    →    2x + 3y  = -9     (2)

Multiply  (1)  by 3   and  (2)  by 8   and we have

-15x - 24y   =   21

16x + 24y   =  -72        add these

  x              =   -51

And using any equation - I'll use (2)  - we can find y

2(-51)  +  3y   = -9

-102 + 3y  = -9      add 102 to both sides

3y  =  93     divide both sides by 3

y =  31

Expand the following: f(i+2) = (i-1+2)^2 (i+2) Add like terms. 2-1 = 1: f(i+2) = (i+2) (i+1)^2 (i+1) (i+1) = (i) (i) + (i) (1) + (1) (i) + (1) (1) = i^2+i+i+1 = i^2+2 i+1: f(i+2) = i^2+2 i+1 (i+2) | | | | i | + | 2 | | i^2 | + | 2 i | + | 1 | | | | i | + | 2 | | 2 i^2 | + | 4 i | + | 0 i^3 | + | 2 i^2 | + | 0 i | + | 0 i^3 | + | 4 i^2 | + | 5 i | + | 2: Answer: | | f(i+2) = i^3+4i^2+5i+2

Example 2    x=4y-11    substitute this 'x' into the first equation

             2x-3y=7

             2(4y-11) -3y=7

            8y -22 - 3y =7

            5y = 7+22

             y= 29/5       Then   since x=4y-11   x=  4 (29/5) -11= 116/5 -55/5= 61/5

1-

Solve the following system: {-7-5 x = 8 y | (equation 1) 3 y = -9-2 x | (equation 2) Express the system in standard form: {-(5 x)-8 y = 7 | (equation 1) 2 x+3 y = -9 | (equation 2) Add 2/5 × (equation 1) to equation 2: {-(5 x)-8 y = 7 | (equation 1) 0 x-y/5 = (-31)/5 | (equation 2) Multiply equation 2 by -5: {-(5 x)-8 y = 7 | (equation 1) 0 x+y = 31 | (equation 2) Add 8 × (equation 2) to equation 1: {-(5 x)+0 y = 255 | (equation 1) 0 x+y = 31 | (equation 2) Divide equation 1 by -5: {x+0 y = -51 | (equation 1) 0 x+y = 31 | (equation 2) Collect results: Answer: | | {x = -51              y = 31

2-

Solve the following system: {2 x-3 y = 7 | (equation 1) x = 4 y-11 | (equation 2) Express the system in standard form: {2 x-3 y = 7 | (equation 1) x-4 y = -11 | (equation 2) Subtract 1/2 × (equation 1) from equation 2: {2 x-3 y = 7 | (equation 1) 0 x-(5 y)/2 = (-29)/2 | (equation 2) Multiply equation 2 by -2: {2 x-3 y = 7 | (equation 1) 0 x+5 y = 29 | (equation 2) Divide equation 2 by 5: {2 x-3 y = 7 | (equation 1) 0 x+y = 29/5 | (equation 2) Add 3 × (equation 2) to equation 1: {2 x+0 y = 122/5 | (equation 1) 0 x+y = 29/5 | (equation 2) Divide equation 1 by 2: {x+0 y = 61/5 | (equation 1) 0 x+y = 29/5 | (equation 2) Collect results: Answer: | | {x = 61/5           y = 29/5

Put in i + 2    for 'x'

(i+2)(i+2-1)^2

(i+2)(i+1)^2

(i+2) (i^2 + 2i + 1)

(i+2)(-1+2i+1)

(i+2)(2i)

2i^2 + 4i  =  4i -2

515991188095162129501590904792840265150804249137905664

The answer is below. Something is malfunctioning.

1217*165 = 200805

[1/2 kg ] / 4   =  1/8 kg each